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2 years ago

11

For an alloy containing 50% cu and 50% ni, calculate the amounts of solid s and liquid l presents at 1300c. show that the total

nickel content in the solid and liquid phases adds up to 50%. (5')

1 answer:

iris [78.8K]2 years ago

3 0

100 %cuni calculate the amounts of solid s and liquid

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How many moles of CaCl₂ are required to produce 45.97 grams of NaCl?

marin [14]

Answer is 0.7866187543

6 0

2 years ago

If an acid/base dissociates completely in water what type of substance is it? Does this mean the acid/base is dangerous?

hram777 [196]

Answer:

1 strong acid

2 yes they are dangerous

Explanation:

Since nearly all of it is dissociated in water, it is called a strong acid.

2 yes Concentrated strong acids can cause severe and painful burns. The pain is due in part to the formation of a protein layer, which resists further penetration of the acid

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3 years ago

The radioactivity due to carbon-14 measured in a piece of a wooden casket from an ancient burial site was found to produce 20 co

bekas [8.4K]

Answer:

17202.6 years

Explanation:

Activity of the living sample (Ao) = 160 counts per minute

Activity of the wood sample (A) = 20 counts per minute

Half life of carbon-14 = 5730 years

t= age of the artifact

From;

0.693/t1/2= 2.303/t log Ao/A

Then;

0.693/ 5730= 2.303/t log Ao/A

Substituting values;

0.693/5730= 2.303/t log (160/20)

Then we obtain;

1.209×10^-4 = 2.0798/t

t= 2.0798/1.209×10^-4

Thus;

t= 17202.6 years

Therefore the artifact is 17202.6 years old.

3 0

2 years ago

If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution

$\Delta T^o$ = freezing point of water

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$w_b$ = mass of solute

$w_a$ = mass of solvent

$M_b$ = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0

3 years ago

Predict what will be observed in each experiment below. experiment predicted observation.

irga5000 [103]

Answer:

The correct answer is -

1. a) The bubbles will shrink, some may vanish.

2. a) Can A will make a louder and stronger fizz than can B.

Explanation:

In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.

Thus, the correct answer would be - The bubbles will shrink, some may vanish

In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.

thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.

8 0

2 years ago