Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2 = mv^2
The correct answer would be B.) 98°c-102°c
Answer:
![T_1=6655.295917 \approx 6655.3N](https://tex.z-dn.net/?f=T_1%3D6655.295917%20%5Capprox%206655.3N)
Explanation:
From the question we are told that
Angle of cable 2 ![\theta=37.0\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D37.0%5Ctextdegree)
Weight of sculpture ![W=5000 N](https://tex.z-dn.net/?f=W%3D5000%20N)
Generally the Tension from cable 2
is mathematically given by
![T_2sin37\textdegree=5000N](https://tex.z-dn.net/?f=T_2sin37%5Ctextdegree%3D5000N)
![T_2=5000N/sin37\textdegree](https://tex.z-dn.net/?f=T_2%3D5000N%2Fsin37%5Ctextdegree)
![T_2=8308.2N](https://tex.z-dn.net/?f=T_2%3D8308.2N)
Generally the Tension from Cable 1
is mathematically given by
![T_1=T_2 cos37\textdegree](https://tex.z-dn.net/?f=T_1%3DT_2%20cos37%5Ctextdegree)
![T_1=8308.2* cos 37\textdegree](https://tex.z-dn.net/?f=T_1%3D8308.2%2A%20cos%2037%5Ctextdegree)
![T_1=6655.295917 \approx 6655.3N](https://tex.z-dn.net/?f=T_1%3D6655.295917%20%5Capprox%206655.3N)
A displacement is a vector quantity that takes into account the shortest distance from the starting point to the endpoint.
The given above gave a time interval in minutes which needs to be converted to seconds. Given that each minute is 60 seconds, 5 minutes equal 300 seconds. To determine the distance, multiply time with speed. The product is 225 m.
Thus, the displacement is 225 m.
Answer: ![1.089\times 10^5\ A](https://tex.z-dn.net/?f=1.089%5Ctimes%2010%5E5%5C%20A)
Explanation:
Given
Charge discharged ![Q=9.7\C](https://tex.z-dn.net/?f=Q%3D9.7%5CC)
time taken ![t=8.9\times 10^{-5}\ s](https://tex.z-dn.net/?f=t%3D8.9%5Ctimes%2010%5E%7B-5%7D%5C%20s)
Current is given as rate of change of discharge i.e.
![\Rightarrow I=\dfrac{Q}{t}\\\\\Rightarrow I=\dfrac{9.7}{8.9\times 10^{-5}}\\\\\Rightarrow I=1.089\times 10^5\ A](https://tex.z-dn.net/?f=%5CRightarrow%20I%3D%5Cdfrac%7BQ%7D%7Bt%7D%5C%5C%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B9.7%7D%7B8.9%5Ctimes%2010%5E%7B-5%7D%7D%5C%5C%5C%5C%5CRightarrow%20I%3D1.089%5Ctimes%2010%5E5%5C%20A)
Therefore, the average current is ![1.089\times 10^5\ A](https://tex.z-dn.net/?f=1.089%5Ctimes%2010%5E5%5C%20A)