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RSB [31]
3 years ago
15

A 0.72 mg sample of phosphorus reacts with bromine to form 10.01 mg of the bromide. part a what is the empirical formula of the

phosphorus bromide
Chemistry
1 answer:
Hatshy [7]3 years ago
3 0
<span>PBr5 You started with 0.72 mg of phosphorus and ended up with 10.01 mg of its bromide. So the amount of bromine is 10.01 - 0.72 = 9.29 mg Now you need to determine the relative number of atoms of each element used. atomic mass of phosphorus = 30.973762 atomic mass of bromine = 79.904 relative atoms of phosphorus = 0.72 / 30.973762 = 0.023245 relative atoms of bromine = 9.29 / 79.904 = 0.116265 Now you need to look for a simple ratio of integers that closely approximates 0.023245 / 0.116265. First we'll divide the larger by the smaller. 0.116265 / 0.023245 = 5.001597 Given how close the value comes to 5. The empirical formula will be PBr5. So for every atom of phosphorus, you need 5 atoms of bromine.</span>
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Which statement describes an Arrhenius acid? A. It is a proton donor. B. It is a proton acceptor. C. It produces hydroxide ions
Katen [24]
Hello.

The answer is: D it produces hyrogen ions in a solution.

This is correct because when Arrhenius acid it turns into hydrogen ions.substance as an acid if it produces hydrogen ions H(+) or hydronium ions in water. A substance is classified as a base if it produces hydroxide ions OH(-) in water.

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3 0
3 years ago
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Which of the following statements about trends in solubility is accurate?
Kipish [7]

"The solubility of gases decreases as temperature rises" statements about trends in solubility is accurate.

<u>Option: D</u>

<u>Explanation:</u>

A substance's solubility is the quantity of that component that is needed at a defined degree of temperature to produce a saturated solution in any set quantity of solvent. Some compounds like hydrochloric acid, ammonia, etc  have solubility that reduces with rising temperature. They are both standard-pressure gases.

When heating a solvent with a gas absorbed in it, both the solvent and the solute spike in the kinetic energy.When the gaseous solute's kinetic energy rises, the molecules have a higher propensity to overcome the solvent molecules' connection and migrate to the gas phase. Thus, a gas's solubility reduces with rising temperature.

4 0
3 years ago
Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The
qaws [65]

Answer:

E_{ionization}=5.45\times 10^{-19}\ J

Explanation:

E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

So, n_i=2 and n_f=\infty (As the hydrogen has to ionize)

Thus,

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J

E_{ionization}=5.45\times 10^{-19}\ J

4 0
3 years ago
HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED
kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0
3 years ago
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White raven [17]

It would be A bc carbon is NOT usually a product. You can find out more about the by searching combustion reactions, then u should be able to answer the questions on your own.

8 0
3 years ago
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