2 mins for sure depending on the distance for walking
Answer:
847.45 N
Explanation:
F₁=force of exerted by smaller piston
F₂=force of exerted by larger piston=1.44×10⁴ N
A₁=Area of smaller piston= 2.62 cm =0.0265 m
A₂=Area of larger piston= 10.8 cm =0.108 m
Pressure exerted by both the pistons will be equal
Hence, force exerted to lift a 14400 N car is 847.45 N
Answer: ratio = 3.14 × 10³⁵
Explanation:
From Newtons law of Universal Gravitation;
Every object in the universe is attracted to every other object
F = (Gm₁m₂)/r²
G = 6.67 X 10⁻¹¹ N-m²/kg²
M₁= mass of one object
M₂= mass of second object
r = distance from center of objects
q = charge = 3.2 x 10⁻¹⁹C.
- Calculating the gravitational force;
Fg = (Gm₁m₂)/r² = (Gm²)/r²
which is = (6.67×10⁻¹¹ × (6.64×10⁻²⁷)²) / r²
= (2.94 × 10⁻⁶³) / r²
- Calculating the electric force;
Fe = (Kq₁q₂) / r² = K q² / r² = (9×10⁹ × (3.2 × 10⁻¹⁹)² / r²
Fe = 9.22 × 10⁻²⁸ / r²
comparing the ratio of both forces we have;
Fe/Fg = (9.22×10⁻²⁸/r²) ÷ (2.94×10⁻⁶³/r²)
r² cancels from the above expression, which gives;
ratio as 3.14 × 10³⁵
