When plane is flying in tail wind condition we will have
Now during return journey we can say its would be head wind now
time = 2 + 1 = 2 hours
now add two equations
distance = 360 miles
now from above equation again
Answer:
x =
Explanation:
Let's start the exercise with the definition of a system formed by the projectile and the block, in this case the forces during the collision are internal and the moment is conserved,
initial instant. Just before the crash
p₀ = m v + 4m 0
final instant. Right after the crash, before the block began to move
= (m + 4m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 5m v_{f}
v_{f} = v/5
knowing the speed of the system (projectile + block) we can use the relationship between work and energy
W = ΔK
starting point. Just when the projectile + block system starts to move
Em₀ = K = ½ m v_{f}²
final point. When the system is stopped
Em_{f} = 0
The work of the friction force is
W = - fr x
the negative sign is because the friction force opposes the motion, let's use Newton's second law to find the friction force
Y Axis
N- W = 0
N = W = mg
The expression for the friction force is
fr = μ N
substituting
fr = μ mg
W = - μ mg x
using the energy duty ratio
- μ mg x = 0 - ½ m
x =
we substitute speed
x =
Answer:
<em>waxing gibbous moon</em>
<em>It comes a week after new moon. <u>A waxing gibbous moon</u> occurs when more than half of the lit portion of the Moon can be seen and the shape increases ("waxes") in size from one day to the next. The waxing gibbous phase occurs between the first quarter and full moon phases.</em>