For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:
Kd = c </span>× α²
α = √(Kd/c) × 100%
Kd = 6.0×10⁻⁷
c(HA) = 0.1M
α = √(6.0×10⁻⁷/0.1) × 100% = 0.23%
So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>
The chemical reaction is written as:
2Zn + O2 = 2ZnO
We are given the amount of the product to be produced from the reaction. We use this value and the relation of the substances in the reaction to calculate what is asked. We do as follows:
2.10 g ZnO ( 1 mol / 81.408 g ) ( 1 mol O2 / 2 mol ZnO ) ( 32 g / 1 mol ) = 0.414 g O2 is needed
Answer:
1.023 J / g °C
Explanation:
m = 37.9 grams
ΔT = 25.0*C
H = 969 J
c = ?
The equation relating these equation is;
H = mcΔT
making c subject of formulae;
c = H / mΔT
c = 969 J / (37.9 g * 25.0*C)
Upon solving;
c = 1.023 J / g °C
Carbonated drinks are a mixture of many compounds such as glucose(sugar) and others, while water is simply its own molecule.
