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Phantasy [73]
4 years ago
11

This problem has been solved! See the answer Determine Um (mode ), average U, and Urms for a group of ten automobiles clocked by

radar at speeds 38,44,48,50,55,55,57,58 and 60mi/h respectively
Chemistry
1 answer:
lara31 [8.8K]4 years ago
4 0

Explanation:

The mode is the most common number.

Um = 55

The mean is the sum of the numbers divided by the quantity.

Uavg = (38 + 44 + 45 + 48 + 50 + 55 + 55 + 57 + 58 + 60) / 10

Uavg = 51

The RMS (root mean square) is the square root of the sum of the squares of the numbers divided by the quantity.

Urms = √[(38² + 44² + 45² + 48² + 50² + 55² + 55² + 57² + 58² + 60²) / 10]

Urms = 51.451

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What is the difference between an atom and an element?
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A particular atom will have the same number of protons and electrons and most atoms have at least as many neutrons as protons. An element is a substance that is made entirely from one type of atom

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3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

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A Variable That Stays The Same In An Experiment Is A ?
hammer [34]
The variable that stays the same in an experiment is called the controlled variable

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3 years ago
What is the density of a liquid if 12.5 ml of the liquid has a density of 9.80 g?
blagie [28]

Answer:

The answer is

<h2>0.784 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of liquid = 9.8 g

volume = 12.5 mL

The density is

density =  \frac{9.8}{12.5}

We have the final answer as

<h3>0.784 g/mL</h3>

Hope this helps you

3 0
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