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Shalnov [3]
4 years ago
5

In determining the distance to a cloud, a meteorologist in a tv station uses radar and notes that a time of 0.2 ms elapses betwe

en the sending and return of a radar pulse. how far away is the cloud?
Physics
1 answer:
katrin2010 [14]4 years ago
5 0
Take the speed of light as 3.00*10^8 m/s
d=vt
d=(300000000*0.002 seconds)/2 (as this is twice the distance to the cloud)
d=300000m
300km


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You are listening to the radio when one of your favorite songs comes on, so you turn up the volume. If you managed to increase t
andrew-mc [135]

To solve this problem we need to apply the corresponding sound intensity measured from the logarithmic scale. Since in the range of intensities that the human ear can detect without pain there are large differences in the number of figures used on a linear scale, it is usual to use a logarithmic scale. The unit most used in the logarithmic scale is the decibel yes described as

\beta_{dB} = 10log_{10} \frac{I}{I_0}

Where,

I = Acoustic intensity in linear scale

I_0 = Hearing threshold

The value in decibels is 17dB, then

17dB = 10log_{10} \frac{I}{I_0}

Using properties of logarithms we have,

\frac{17}{10} = log_{10} \frac{I}{I_0}

log_{10} \frac{I}{I_0} = 1.7

\frac{I}{I_0} = 10^{1.7}

\frac{I}{I_0} = 50.12 W/m^2

Therefore the factor that the intensity of the sound was 50.12W/m^2

5 0
3 years ago
A man does 500 j work pushing a car a distance of 2m how much force does he apply
olasank [31]

Answer: 250 N

Explanation:

Use equation for work

W=F*d

d=2m

W=500J

F=?

-----------------------

W=Fd

F=W/d

F=500J/2m

F=250N

6 0
4 years ago
Read 2 more answers
Which descriptions best fit the labels? X: kinetic energy Y: potential energy X: potential energy Y: kinetic energy X: mechanica
GalinKa [24]

its the 3rd option!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0
4 years ago
Read 2 more answers
Can someone help me with this question
Mademuasel [1]

Answer:

Net force: 20 N to the right

mass of the bag: 20.489 kg

acceleration:  0.976  m/s^2

Explanation:

Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:

195 N - 175 N = 20 N

So net force on the bag is 20 N to the right.

The mass of the bag can be found using the value of the weight force: 201 N:

mass = Weight/g = 201 / 9.81 = 20.489 kg

and the acceleration of the bag can be found as the net force divided by the mass we just found:

acceleration = 20 N / 20.489 kg = 0.976  m/s^2

8 0
3 years ago
A magnetic B field of strength 0.9 T is perpendicular to a loop with an area of 3 m2. If the area of the loop is reduced to zero
Alexeev081 [22]

Answer:

The magnitude of induced emf is 5.4 V

Explanation:

Given:

Magnetic field B = 0.9 T

Area of loop \Delta A = 3 m^{2}

Time take to reduce loop to zero \Delta t = 0.5 sec

To find induced emf we use faraday's law,

Induced emf is given by,

  \epsilon = -\frac{\Delta \phi}{\Delta t}

Here minus sign shows lenz law, for finding magnitude of emf  we ignore it.

Where \phi = B\Delta A

Put the value of flux and find induced emf,

   \epsilon = \frac{B\Delta A}{\Delta t}

   \epsilon = \frac{0.9 \times 3}{0.5}

   \epsilon = 5.4 V

Therefore, the magnitude of induced emf is 5.4 V

3 0
4 years ago
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