Answer:
c = 4
Explanation:
In general, for the reaction
a A + b B ⇒ c C + d D
the rate is given by:
rate = - 1/a ΔA/Δt = - 1/b ΔB/Δt = + 1/c ΔC/Δt = + 1/d ΔD/Δt
this is done so as to express the rate in a standarized way which is the same to all the reactants and products irrespective of their stoichiometric coefficients.
For this question in particular we know the coefficient of A and need to determine the coefficient c.
- 1/2 ΔA/Δt = + 1/c ΔC/Δt
- 1/2 (-0.0080 ) = + 1/c ( 0.0160 mol L⁻¹s⁻¹ )
0.0040 mol L⁻¹s⁻¹ c = 0.0160 mol L⁻¹s⁻¹
∴ c = 0.0160 / 0.0040 = 4
They are of the same period and are similar in some form
Answer:
i think the answer is helium (top right in periodic table)
The formula for Cs and S is Cs₂S.
For Cs and S,
Ions formed will be Cs⁺ and S²⁻
As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -
For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.
Cs have 1 valence electron and S have 6 valence electrons.
Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.
Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.
The formula is Cs₂S.
To learn more about electronic configuration, visit: brainly.com/question/15051483
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