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DaniilM [7]
3 years ago
8

Astronomers use radio waves to learn about the universe. Radio waves travel light-years through space before reaching Earth. Rad

io waves must be which type of wave
Physics
1 answer:
IrinaVladis [17]3 years ago
4 0
Electromagnetic wave, a transverse wave
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What does strong language mean ?
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Answer:

noun

the style of a piece of writing or speech.

"he explained the procedure in simple, everyday language"

coarse or offensive language.

noun: strong language

"strong language"

Explanation:

comment how it helps

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What force is used to make the back-and-forth motion of a swing higher?
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its a

Explanation:

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Prove(show) ''T=2π√(l/g)''​
Nonamiya [84]

Answer:

Time period for Simple pendulum, T=2\pi\sqrt{\frac{l}{g}

Explanation:

The Simple Pendulum

Consider a small bob of mass m is tied to extensible string of length l that is fixed to rigid support. The bob is oscillating in the plane about verticle.

       Let \theta is the angle made by string with vertical  during oscillation.

Vertical component of the force on bob, F=-mg\sin\theta

Negative sign shows that its opposing the motion of bob.

Taking \theta as very small angle then, \sin\theta\sim\theta

F=-mg\theta    

Let x is the displacement made by bob from its mean position ,

then, \theta=\frac{x}{l}

so, F=-mg\frac{x}{l}                ........(1)

Since, pendulum is in hormonic motion,

as we know, F=-kx

where k is the constant and k=m\omega^{2}

F=-m\omega^2x                   .........(2)

From equation (1) and (2)

-m\omega^2x=-mg\frac{x}{l}

\omega=\sqrt{\frac{g}{l}}

Since, \omega=\frac{2\pi}{T}

\frac{2\pi}{T}=\sqrt{\frac{g}{l}

T=2\pi\sqrt{\frac{l}{g}}

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3 years ago
Does change in direction affect the acceleration of a car?
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A change in velocity is either a change in an object's speed or its direction. When a moving object changes direction, its velocity changes and it is accelerating.

Explanation:

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A horizontal spring with spring constant of 9.80 N/m is attached to a block with a mass of 1.20 kg that sits on a frictionless s
Andreas93 [3]

Answer:

Explanation:

Given

at certain point displacement and velocity is 0.345 m and 0.54 m/s

Therefore Potential and Kinetic Energy associated is

U=\frac{1}{2}kx^2

U=\frac{1}{2}\times 9.8\times (0.345)^2

U=0.583 J

Kinetic Energy K=\frac{1}{2}mv^2

k=\frac{1}{2}\times 1.2\times (0.54)^2=0.174 J

Total Energy T=U+K=0.583+0.174=0.757 J

Total Energy is conserved hence at maximum displacement  all energy will be Potential energy

T=\frac{1}{2}kA^2

where A=maximum displacement

0.757=\frac{1}{2}\times 9.8\times A^2

0.1544=A^2

A=0.393 m

Maximum speed occurs at equilibrium Position where Potential Energy is zero

thus T=\frac{1}{2}mv^2

0.757=\frac{1}{2}\times 1.2\times v_{max}^2

v_{max}=1.123 m/s

(c)When block is at 0.2 m from Equilibrium speed then its Potential Energy is

U=\frac{1}{2}kx^2=\frac{1}{2}\times 9.8\times (0.2)^2=0.196 J

T=U+K

K=0.757-0.196=0.561 J

K=\frac{1}{2}mv^2

0.561=\frac{1}{2}\times 1.2\times v^2

v=0.966 m/s

7 0
3 years ago
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