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Alex Ar [27]
3 years ago
5

A car travels at a speed of 25 m/s on a flat stretch of road. The driver must maintain pressure on the accelerator to keep the c

ar moving at this speed. What is the net work done on the car over a distance of 250 m?
Physics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

zero

Explanation:

Speed is constant so, the acceleration is zero and hence the force is zero. So the work done is defined as he product of force and the distance traveled in the direction of force.

W = F x d

W = 0 x 250

W = 0 J

Thus, the work done is zero.

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How many protons does Silicone have<br><br> A.2<br> B.14<br> C.28<br> D.28.08
taurus [48]

Answer:

14

Explanation:

the left top is protons

hope this helps :)

3 0
3 years ago
A 5kg ball is on top of the school building at a height of 40m above the ground.
mojhsa [17]

Answer:

A-Caclcuate the potential energy of the ball at that height

Explanation:

(a). Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

3 0
2 years ago
Three conducting plates, each of area A, are connected as shown.
Shkiper50 [21]
You have effectively got two capacitors in parallel. The effective capacitance is just the sum of the two. 
Cequiv = ε₀A/d₁ + ε₀A/d₂ Take these over a common denominator (d₁d₂) 
Cequiv = ε₀d₂A + ε₀d₁A / (d₁d₂) Cequiv = ε₀A( (d₁ + d₂) / (d₁d₂) ) 
B) It's tempting to just wave your arms and say that when d₁ or d₂ tends to zero C -> ∞, so the minimum will occur in the middle, where d₁ = d₂ 
But I suppose we ought to kick that idea around a bit. 
(d₁ + d₂) is effectively a constant. It's the distance between the two outer plates. Call it D. 
C = ε₀AD / d₁d₂ We can also say: d₂ = D - d₁ C = ε₀AD / d₁(D - d₁) C = ε₀AD / d₁D - d₁² 
Differentiate with respect to d₁ 
dC/dd₁ = -ε₀AD(D - 2d₁) / (d₁D - d₁²)² {d2C/dd₁² is positive so it will give us a minimum} For max or min equate to zero. 
-ε₀AD(D - 2d₁) / (d₁D - d₁²)² = 0 -ε₀AD(D - 2d₁) = 0 ε₀, A, and D are all non-zero, so (D - 2d₁) = 0 d₁ = ½D 
In other words when the middle plate is halfway between the two outer plates, (quelle surprise) so that 
d₁ = d₂ = ½D so 
Cmin = ε₀AD / (½D)² Cmin = 4ε₀A / D Cmin = 4ε₀A / (d₁ + d₂)
7 0
3 years ago
In the deep ocean, a water wave with wavelength 95 m travels at 12 m/s. Suppose a small boat is at the crest of this wave, 1.2 m
dimaraw [331]

Answer:

the vertical position is 1.1971m

Explanation:

Recall that

y = 1.2 * cos (\frac{2*\pi * distance travelled}{wavelenght})

recall that v = \frac{distance}{time}

thus;  distance =  v* t

this implies that distance = 12 * 5.0

                                          =  60

therefore;  y = 1.2 cos \frac{2*3.142*60}{95}

                  y = 1.1971m

the

3 0
3 years ago
Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much
____ [38]

Answer:

T = 6.75\,N\cdot m

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

T = F\cdot r \cdot \sin \theta

T = F_{\bot} \cdot r

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

T = (15\,N)\cdot (0.45\,m)

T = 6.75\,N\cdot m

8 0
3 years ago
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