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Alex Ar [27]
3 years ago
5

A car travels at a speed of 25 m/s on a flat stretch of road. The driver must maintain pressure on the accelerator to keep the c

ar moving at this speed. What is the net work done on the car over a distance of 250 m?
Physics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

zero

Explanation:

Speed is constant so, the acceleration is zero and hence the force is zero. So the work done is defined as he product of force and the distance traveled in the direction of force.

W = F x d

W = 0 x 250

W = 0 J

Thus, the work done is zero.

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You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget
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Answer:

35.7 m

Explanation:

Let

\mid A\mid=18.5 m

\mid B\mid=41 m

We have to find the distance between Joe's and Karl'e tent.

A_x=Acos\theta

A_y=Asin\theta

Substitute the values then we get

A_x=18.5cos23^{\circ}=17 m

A_y=18.5sin 23^{\circ}=7.2 m

B_x=41cos37.5^{\circ}=32.5 m

B_y=41sin37.5^{\circ}=-24.96 m

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

B=A+C

C=B-A

C_x=B_x-A_x=32.5-17=15.5 m

C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m

\mid C\mid=\sqrt{C^2_x+C^2_y}

\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m

Hence, the distance between Joe's and Karl's tent=35.7 m

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the correct choice is

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