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Anastasy [175]
3 years ago
9

Which substance is translucent​clear glasscream cheesetissue paperorange juice

Physics
2 answers:
babymother [125]3 years ago
7 0
A. clear glass.

explanation:

Examples of transparent items are glass, water, and air.
Materials that allow some light to pass through them are called translucent.
If an object does not allow any light to pass through it then it is opaque.
irina1246 [14]3 years ago
6 0
It’s A clear glass translucent is basically transparent
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Is (2, 2) a solution of y &lt; 4x-6<br> Help
vesna_86 [32]

Answer:

B) No.

Explanation:

Okay,so,

this is equation is y=mx +b

mx represents the slope

and b represents the y-intercept

in order to figure this out you need to plot the y-intercept first

that makes its (0,-6) because the 6 is negative in the equation

4x is also equal to 4/1 since we dont know what x is

we have to do rise over run for this

you go up 4 spots on the y intercept from -6 because 4 is positive

then you go to the right 1 time because 1 is positive.

this leaves you at (1,-2)

so, (2,2) is NOT a solution

7 0
3 years ago
Does air resistance affect the motion of a falling object differently when the initial velocity of the object is greater?
DIA [1.3K]
Yes. Even greater. Air resistance or drag becomes harder the faster an object goes. This is why when cars reach their max speed they don't accelerate as fast, because they are pushing harder against the wind. If I take a tennis ball and shoot it down a bottomless pit, a 400 kph, the drag will slow the ball down till it reaches terminal velocity. 
4 0
3 years ago
Read 2 more answers
A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3.0 m is initially at rest. A 20 kg boy approaches the m
nekit [7.7K]

Answer:

The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s

Explanation:

The rotational inertia of the merry-go-round = 600 kg·m²

The radius of the merry-go-round = 3.0 m

The mass of the boy = 20 kg

The speed with which the boy approaches the merry-go-round = 5.0 m/s

F_T \cdot r = I \cdot \alpha  = m \cdot r^2  \cdot \alpha

Where;

F_T = The tangential force

I =  The rotational inertia

m = The mass

α = The angular acceleration

r = The radius of the merry-go-round

For the merry go round, we have;

I_m \cdot \alpha_m  = I_m \cdot \dfrac{v_m}{r \cdot t}

I_m = The rotational inertia of the merry-go-round

\alpha _m = The angular acceleration of the merry-go-round

v _m = The linear velocity of the merry-go-round

t = The time of motion

For the boy, we have;

I_b \cdot \alpha_b  = m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t}

Where;

I_b = The rotational inertia of the boy

\alpha _b = The angular acceleration of the boy

v _b = The linear velocity of the boy

t = The time of motion

When the boy jumps on the merry-go-round, we have;

I_m \cdot \dfrac{v_m}{r \cdot t} = m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t}

Which gives;

v_m = \dfrac{m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t} \cdot r \cdot t}{I_m} = \dfrac{m_b \cdot r^2  \cdot v_b}{I_m}

From which we have;

v_m =  \dfrac{20 \times 3^2  \times 5}{600} =  1.5

The velocity of the merry-go-round, v_m, after the boy hops on the merry-go-round = 1.5 m/s.

5 0
2 years ago
Experiencing a green afterimage of a red object is most easily explained by
il63 [147K]

Answer:

The opponent-process theory

Explanation:

The opponent process theory is based on the human visual system and according to the theory the interpretation of the color is done by the photo-receptors rods and cones in the human eye.

This theory states that the perception of color is governed by the two opponent system which includes - a red-green, a blue-yellow and a black-white mechanism.

Any activity in one of these restricts the activity in the other.

4 0
3 years ago
Read 2 more answers
A person pushes two boxes with a horizontal force F of magnitude of 100 N.
Monica [59]

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

  • m_A = 9\  kg

Mass of box B,

  • m_B = 2 \ kg

Horizontal force,

  • F_{app} = 100 \ N

From the Newton's law,

→ F_{app} = (\frac{F_{app}}{m_A+m_B} )a

or,

→      a = \frac{F_{app}}{(m_A+m_B)}

Bu substituting the values, we get

→         = \frac{100}{9+2}

→         = \frac{100}{11}

→         9.10 \ m/s^2

We can see that between the two boxes, the action-reaction pair exist.

then,

→ F_{action-reaction} = m_b \ a

→                          =2\times 9.10

→                          = 18.2 \ N (magnitude)

Thus the above solution is appropriate.

 

Learn more about the magnitude here:

brainly.com/question/13545862

7 0
2 years ago
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