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3 years ago

Which is an example of a multicellular organism? A. gorilla B. amoeba C. bacterium D. paramecium

Physics

1 answer:

IgorLugansk [536]3 years ago

4 0

The answer is A: Gorilla.

In the animal kingdom, all organisms are multicelluar.

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Two carts connected by a 0.05 m spring hit a wall, compressing the spring to 0.02 m. The spring constant k is

vivado [14]

Answer:

0.045 J

Explanation:

From the question,

The elastic potential energy stored in a spring is given as,

E = 1/2ke²...................... Equation 1

Where E = elastic potential energy, k = spring constant, e = compression.

Given: k = 100 N/m, e = 0.05-0.02 = 0.03 m

Substitute these values into equation 1

E = 1/2(100)(0.03²)

E = 50(9×10⁻⁴)

E = 0.045 J

Hence the right option is 0.045 J

4 0

3 years ago

B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

$V_{int}=\sqrt{U^2+19.6H}$

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration is mathematically given as

$a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2$

Where

acceleration is still -9.81 m/s2,

Hence,

$V^2-U^2=2(-9.81)*-H$

Therefore

$V_{int}=\sqrt{U^2+19.6H}$

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

7 0

2 years ago

* CRIMINOLOGY*

Setler [38]

I think the answer is B.

Hope this helps.

5 0

3 years ago

Read 2 more answers

Two electrons are passing 20.0 mm apart. What is the electric repulsive force that they exert on each other

vladimir1956 [14]

15.0 I’m pretty sure that’s the answer to your question

4 0

2 years ago

Read 2 more answers

A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is

SpyIntel [72]

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

$E = \frac{hc}{\lambda}\\\\$

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

$E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}$

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

$Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\$

<u>n = 4 x 10¹⁸ photons</u>

8 0

3 years ago