Answer:
It is less dense than oxygen gas.
Explanation:
Density is a physical property. Reactivity, flammability, and acid compounds are all chemical properties.
Hope that helps.
Answer:
pH of soltion will be 5.69
Explanation:
The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.
The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:
![pH=pKa+log(\frac{[salt]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%29)


The moles of acid taken :

The moles of base taken:

The moles of acid left after reaction :

The moles of salt formed = 4.5mmol
Putting values in equation
![pH=pKa+log(\frac{[salt]}{[acid]} )=4.74+log(\frac{4.5}{0.5})=5.69](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%29%3D4.74%2Blog%28%5Cfrac%7B4.5%7D%7B0.5%7D%29%3D5.69)
Energy lost to condense = 803.4 kJ
<h3>Further explanation</h3>
Condensation of steam through 2 stages:
1. phase change(steam to water)
2. cool down(100 to 0 C)
1. phase change(condensation)
Lv==latent heat of vaporization for water=2260 J/g

2. cool down
c=specific heat for water=4.18 J/g C

Total heat =

<span>If you drop a bath bomb into water then it will start to fizz. It will fizz because there is a chemical reaction from the different ingredients taking place meaning that these ingredients react to water.
</span>
Answer:
This is the conversion factor, we have to use:
44 g / 1mol
Explanation:
The reaction for the methane combustion is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First of all we use this conversion factor to determine the moles of methane, we used.
50.6 g . 1 mol / 16 g = 3.16 mol
So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂
To calculate the grams of produced dioxide:
3.16 mol . 44 g / 1mol = 139.04 g