I think it's Selenium disulfide
        
             
        
        
        
Answer:
81% Yield
Explanation:
2CO        +               O₂                                =>     2CO₂
Excess                3.70g O₂                          =>     8.25g CO₂ (actural yield)
                (3.70g O₂)/(32g O₂/mol O₂)
                    = 0.1156 mol O₂                       =>  2(0.1156) mol CO₂
                                                                           = 10.175g (Theoretical Yield)
%Yield = (Actual Yield / Theoretical Yield)100%  
= (8.25g/10.175g)100% = 81% Yield
 
        
             
        
        
        
Answer: 3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL