Friction is a force. A resistance force that tries to slow down and stop objects in motion. The difference between friction and air resistance is that friction acts on surfaces. For example, if I were skateboarding on a rough surface, more friction would occur so I would travel slower. If I were skareboarding on ice, I would go faster because there is much less friction to slow me down. Hope that helps:)
Answer:
In regards to the global energy budget, Earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave</u> radiation.
Explanation:
It is required to tell what kind of wave radiation the earth absorbs and emits in regards to the global energy budget.
Let us discuss the global energy budget first.
The balance between the solar energy that enters Earth and the energy that leaves Earth and travels back into space is known as the global energy budget or the earth's energy budget. The visible region of the electromagnetic spectrum is where the majority of the sun's energy is found.
Therefore earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave </u>radiation in regard to the global energy budget.
To know more about, the global energy budget, refer to:
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Answer:
B according to the picture
Explanation:
Star of 3 stellar masses => red supergiant=>supernova=>neutron star
The electric potential V(z) on the z-axis is : V =
The magnitude of the electric field on the z axis is : E = kб 2( 1 - [z / √(z² + a² ) ] )
<u>Given data :</u>
V(z) =2kQ / a²(v(a² + z²) ) -z
<h3>Determine the electric potential V(z) on the z axis and magnitude of the electric field</h3>
Considering a disk with radius R
Charge = dq
Also the distance from the edge to the point on the z-axis = √ [R² + z²].
The surface charge density of the disk ( б ) = dq / dA
Small element charge dq = б( 2πR ) dr
dV ----- ( 1 )
Integrating equation ( 1 ) over for full radius of a
∫dv =
V =
=
Therefore the electric potential V(z) =
Also
The magnitude of the electric field on the z axis is : E = kб 2( 1 - [z / √(z² + a² ) ] )
Hence we can conclude that the answers to your question are as listed above.
Learn more about electric potential : brainly.com/question/25923373