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Vesna [10]
3 years ago
14

Help

Physics
2 answers:
Rashid [163]3 years ago
8 0
Box A: sulfur trioxide

Box B: carbon monoxide

Box C: nitrogen dioxide
aleksley [76]3 years ago
6 0
A- sulfur oxide
B- carbon monoxide
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A 2000 kg car moves along a horizontal road at speed vo
cluponka [151]

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a (Eq. 1)

\Sigma F_{y} = N-m\cdot g = 0 (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

a = -\mu_{k}\cdot g (Eq. 3)

Where:

a - Deceleration of the car, measured in meters per square second.

\mu_{k} - Kinetic coefficient of friction, dimensionless.

g - Gravitational acceleration, measured in meters per square second.

If we know that \mu_{k} = 0.0735 and g = 9.807\,\frac{m}{s^{2}}, then deceleration of the car is:

a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )

a = -0.721\,\frac{m}{s^{2}}

The stopping distance of the car (\Delta s), measured in meters, is determined from the following kinematic expression:

\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a} (Eq. 4)

Where:

v_{o} - Initial speed of the car, measured in meters per second.

v - Final speed of the car, measured in meters per second.

If we know that v_{o} = 15.9\,\frac{m}{s}, v = 0\,\frac{m}{s} and a = -0.721\,\frac{m}{s^{2}}, stopping distance of the car is:

\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}

\Delta s = 175.319\,m

The shortest possible stopping distance of the car is 175.319 meters.

8 0
3 years ago
What is the deceleration of a bicycle that goes from 40m/s to 20m/s in 5 seconds
Alex Ar [27]

Answer:

-4 m/s^2

Explanation:

The acceleration of the bycicle is given by:

a=\frac{v-u}{t}

where

v = 20 m/s is the final velocity of the bike

u = 40 m/s is the initial velocity

t = 5 s is the time interval

Substituting numbers, we find

a=\frac{20 m/s-40 m/s}{5s}=-4 m/s^2

and the acceleration is negative, which means that the bycicle is slowing down.

5 0
3 years ago
Explain how high energy electrons are used in electron transport
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High energy electrons & hydrogen ions from NADH & FADH2 produced in the Krebs cycle used to convert ADP to ATP
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4 (a) (1) Which lens is a converging lens with the greatest power?
SOVA2 [1]

Answer:

Answer

Explanation:

please like and mark be mrain list

3 0
2 years ago
A plane coming in to land at a busy airport is asked to circle the airport until the air traffic congestion eases off. The pilot
Ber [7]

Answer:

The solution is given in the picture attached below

Explanation:

8 0
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