Answer:
640.59 g of NaCl.
Explanation:
Using Boiling point elevation,
ΔTb = kb * i * b
Where,
b = molality
kb = 0.52 °C kg/mole
i = van't koff factor
ΔTb = ΔTsol - ΔTsolv
= 2°C
2 = 0.52 * b
= 3.846 mol/kg.
Mass of water, solvent = 2.85 kg
Molality is the ratio of the number of moles of the solute to the mass of the solvent.
= 3.846 * 2.85
= 10.96 mol.
Mass of NaCl = molar mass * number of moles
= 58.44 * 10.96
= 640.59 g of NaCl.
Answer:
The correct answer is
a little less than 15 km/s.
Explanation:
The distance between the sun and Jupiter varies by about 75 million km between the perihelion and the aphelion with an average distance of 778 million km from the sun for which it takes Jupiter about 12 years to complete its orbit round the sun giving it an orbital speed of about 13.07 km/s
The size of Jupiter is more than the twice the combined size of all the other planets, which is about 1.300 times the size of earth.
F = m × g
Now when, a force acts on the object at an angle and in downwards, thus formula becomes:
= N = mg + F sin(x)
Here,
- N = normal force, m = mass , g = acceleration due to gravity, F = outside force, x = the angle formed
See, as we habe to calculate the weight, which is m × g, thus we will recreate thus formula like thus:
= N = w + F sin(x) --------- [Weight = w]
Now, the solutions becomes easy from here, just put the values:
= N = w + F sin(x)
= 200 = w + 90 × sin(32)
= 200 = w + 90 × 0.55
= 200 = w + 49.5
= 200 - 49.5 = w
= 150.5 = w
I have got my answer but in approx, hope you will not mind. ^^"
Answer:
You use a force of 150 N to push a 30 kg crate across the floor for a distance of 10 m. If the crate is moving at a speed of 5 m/s…
Answer:
Acceleration, a = -31.29 m/s²
Explanation:
It is given that, Initial speed of the aircraft, u = 140 mi/h =
62.58 m/s
Finally, it stops, v = 0
Time taken, t = 2 s
Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :
a = t
0-62.58 2 a =
a = -31.29 m/s²
So, the acceleration of the aircraft is 31.29 m/s²
and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)