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F = m × g
Now when, a force acts on the object at an angle and in downwards, thus formula becomes:
= N = mg + F sin(x)
Here,
- N = normal force, m = mass , g = acceleration due to gravity, F = outside force, x = the angle formed
See, as we habe to calculate the weight, which is m × g, thus we will recreate thus formula like thus:
= N = w + F sin(x) --------- [Weight = w]
Now, the solutions becomes easy from here, just put the values:
= N = w + F sin(x)
= 200 = w + 90 × sin(32)
= 200 = w + 90 × 0.55
= 200 = w + 49.5
= 200 - 49.5 = w
= 150.5 = w
I have got my answer but in approx, hope you will not mind. ^^"
Answer:
Acceleration, a = -31.29 m/s²
Explanation:
It is given that, Initial speed of the aircraft, u = 140 mi/h =
62.58 m/s
Finally, it stops, v = 0
Time taken, t = 2 s
Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :
a = t
0-62.58 2 a =
a = -31.29 m/s²
So, the acceleration of the aircraft is 31.29 m/s²
and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)
Acceleration, a = -31.29 m/s²
Explanation:
It is given that, Initial speed of the aircraft, u = 140 mi/h =
62.58 m/s
Finally, it stops, v = 0
Time taken, t = 2 s
Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :
a = t
0-62.58 2 a =
a = -31.29 m/s²
So, the acceleration of the aircraft is 31.29 m/s²
and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)