Answer:
Explanation:
Applying Forces, doing Work and developing Power. Applying Forces: Force is a push or a pull and many forces are acting on you all of the time. ... possible to stretch the rubber band with one hand using your thumb and finger at two different places but ... If you are smart, however, just exerting forces, shouldn't get you tired
Answer:
The electric field strength at the midpoint of the line joining the charges is zero (0)
Explanation:
Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.
Complete Question
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.08m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 2.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2
Answer:
The acceleration due to gravity is
Explanation:
From the question we are told that
The length of the simple pendulum is 
The number of cycles is 
The time take is
Generally the period of this oscillation is mathematically evaluated as

substituting values


The period of this oscillation is mathematically represented as

making g the subject of the formula we have
![g = \frac{L}{[\frac{T}{2 \pi } ]^2 }](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7BL%7D%7B%5B%5Cfrac%7BT%7D%7B2%20%5Cpi%20%7D%20%5D%5E2%20%7D)

Substituting values

3.
a)
r = distance of each mass in each hand from center = 0.6 m
m = mass of each mass in each hand = 2 kg
v = linear speed = 1.1 m/s
L = combined angular momentum of the masses = ?
Combined angular momentum of the masses is given as
L = 2 m v r
L = 2 (2) (1.1) (0.6)
L = 2.64 kg m²/s
b)
v' = linear speed when she pulls her arms = ?
r' = distance of each mass from center after she pulls her arms = 0.15 m
Using conservation of momentum , angular momentum remains same, hence
L = 2 m v' r'
2.64 = 2 (2) (0.15) v'
v' = 4.4 m/s