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2 years ago

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A bomber flies horizontally with a speed of 323 m/s relative to the ground. The altitude of the bomber is 3580 m and the terrain

is level. Neglect the effects of air resistance. The acceleration of gravity is 9.8 m/s 2 . How far from the point vertically under the point of release does a bomb hit the ground? Answer in units of m.

1 answer:

Alex17521 [72]2 years ago

8 0

Answer:8730.63 m

Explanation:

Given

Bomber velocity $u=323 m/s$ relative to ground

Altitude of the bomber $h=3580 m$

Range of bomb when bomb when it is released is given by

$R=u\times t$

where $u =velocity\ of\ Bomber$

Horizontal velocity of bomber is equal to bomb horizontal velocity

time taken by to cover 3580 m

$h=ut+\frac{at^2}{2}$

$3580=0+\frac{9.8\times t^2}{2}$

$t^2=\frac{7160}{9.8}$

$t=27.03 s$

Therefore range of bomb is

$R=323\times 27.03=8730.63 m$

Therefore bomber must release the bomb at a horizontal distance of 8730.63 m before the hit point

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