The reaction is as follows:
2 H₂(g) + O₂(g) → 2 H₂O(g) . ΔH = - 483.5 kJ
Using the change in enthalpy and heat, calculate the moles as follows:
Moles of H₂ = -
x 2 mol H₂
= - 216 kJ / (-483.5 kJ) x 2 mol H₂
= 0.893 mol H₂
Calculate the mass of H₂ using the moles and molar mass as follows:
0.893 mol H₂ x (2.02 g H₂ / 1 mol H₂) = 1.79 g H₂
Therefore, the mass of hydrogen gas is 1.79 g
Density of a liquid determines how it will layer (heaviest to lightest). If the liquid is least dense it will float to the bottom. Layers will remain separated because each liquid is actually floating on top of the more dense liquid beneath it.
Answer:
Total pressure at equilibrium is 0.2798atm.
Explanation:
For the reaction:
H₂S(g) ⇄ H₂(g) + S(g)
Kp is defined as:
If initial pressure of H₂S is 0.150 atm, equilibrium pressures are:
H₂S(g): 0.150atm - x
H₂(g): x
S(g): x
Replacing in Kp:
X² = 0.1251 - 0.834X
X² + 0.834X - 0.1251 = 0
Solving for X:
X = -0.964 → False solution: There is no negative pressures
X = 0.1298
Thus, pressures are:
H₂S(g): 0.150atm - 0.1298atm = <em>0.0202atm</em>
H₂(g): <em>0.1298atm</em>
S(g): <em>0.1298atm</em>
Thus, total pressure in the container at equilibrium is:
0.0202atm + 0.1298atm + 0.1298atm = <em>0.2798atm</em>
The answer would be W and Z
The inverse proportion is PV = k
We can write the equation as <em>P</em> = k/<em>V</em> or <em>P</em> ∝ 1/<em>V</em>. Thus, <em>P</em> and <em>V</em> are <em>inversely related</em>.
We can rewrite <em>V</em>= T/k as <em>V</em> = k<em>T</em> or <em>V</em> ∝ <em>T</em>. Thus,<em> V</em> is <em>directly proportiona</em>l to <em>T</em>
.
<em>F</em> = -k<em>x</em>² is <em>neither a direct nor an invers</em>e relation.
<em>y</em> = k<em>x</em> – 8 is a linear relation, but it is <em>not a direct proportion</em> because of the “-8” term.