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Lostsunrise [7]
3 years ago
9

1. The density of gasoline is 0.7 g/ml. What is the mass of 400L of gasoline?

Chemistry
1 answer:
elena-s [515]3 years ago
5 0

Answer:

280,000g

Explanation:

0.7g/mL x 1000mL/1L x 400L = 280,000g

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A gas that has a volume of 28 liters, a temperature of 45C, And an unknown pressure has its volume increased to 34 liters and it
patriot [66]

Answer:

P1 = 2.5ATM

Explanation:

V1 = 28L

T1 = 45°C = (45 + 273.15)K = 318.15K

V2 = 34L

T2 = 35°C = (35 + 273.15)K = 308.15K

P1 = ?

P2 = 2ATM

applying combined gas equation,

P1V1 / T1 = P2V2 / T2

P1*V1*T2 = P2*V2*T1

Solving for P1

P1 = P2*V2*T1 / V1*T2

P1 = (2.0 * 34 * 318.15) / (28 * 308.15)

P1 = 21634.2 / 8628.2

P1 = 2.5ATM

The initial pressure was 2.5ATM

3 0
3 years ago
To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
Phoenix [80]

Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

T_1 = initial temperature of gas = 0^oC=273.15 K

V_1 = initial volume of gas = 310 cm^3 = 310 mL = 0.310 L

(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

V_2 = final volume of gas = ?

P_2V_2=nRT_2..[2]

By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

3 0
3 years ago
Read 2 more answers
When there are no decomposers, what happens to the grass?
zavuch27 [327]

Answer:

if there would have been no decomposers on Earth, the whole of the Earth would have been filled with dead and decaying matter of plants and animals.

Explanation:

I hope this helps :3

6 0
3 years ago
Read 2 more answers
A block of metal has a volume of 14.0in3 and weighs 5.16 lb .
riadik2000 [5.3K]

The density of metal block in grams per cubic centimeter is 10.70 g/cm³.

Given,

Mass of metal block = 5.16 lb  

1 lb = 453.592 g

5.26 lb = 2340.536 g

The volume of metal block = 14 in 3

1 in = 2.5 cm

1 in 3 = 15.625 cm³

14 in 3 = 218.75 cm³

Density is defined as the mass per unit volume of a substance. Or, it is the ratio of mass to the volume of the substance.

As we know,

Density = mass/volume

Or, density = 2340.536 / 218.75

Or, density = 10.70 g/cm³

Therefore, the density of the metal block is 10.70 g/cm³.

To learn more about the density, visit: brainly.com/question/15164682

#SPJ9

5 0
2 years ago
Why is zinc not extracted from ZnO through reduction using CO?​
Jet001 [13]
The standard Gibbs free energy of formation of ZnO from Zn is lower than that of CO2 from CO. Therefore, CO cannot reduce ZnO to Zn. Hence, Zn is not extracted from ZnO through reduction using CO
6 0
1 year ago
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