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maksim [4K]
3 years ago
8

A car accelerates uniformly from rest and reaches a speed of 18 m/s in 13.8 s. the diameter of a tire is 60.8 cm. find the numbe

r of revolutions the tire makes during this motion, assuming no slipping.
Physics
1 answer:
Sav [38]3 years ago
6 0
The area under a velocity time graph is distance travelled (as integrating velocity gives distance), so we can imagine the v/t as a line, giving a triangle with 2 sides of 13.8 and 18. The area of a triangle is bh/2, so 9*13.8 = 124.2m which is how far the car travelled in that time.
60.8cm is 0.608m, and now we can divide to work out the number of revolutions:
124.2/0.608 = 204.28 = 204 revolutions to 3sf (number of sf in the question assuming 18 is in fact 18.0, so the number you should give your answer to)
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The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

The potential energy increases by 3773 J

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Using 0.500 g of nichrome, you are asked to fabricate a wire with uniform cross-section. The resistance of the wire is 0.673 Ω.
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Explanation:

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The resistance of the wire, R = 0.673 ohms

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(A) The length of the wire is given by using the definition of resistance as :

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V=A\times l\\\\A=\dfrac{V}{l}\\\\Since, V=\dfrac{m}{d}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{0.5\times 10^{-3}}{8.31\times 10^3}\\\\V=6.01\times 10^{-8}\ m^3

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Hence, this is the required solution.                                                                  

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