Leonardo de Vinci, Michelangelo, and Raphael.
Answer is: Ksp for strontium arsenate is 2.69·10⁻¹⁸.
Balanced chemical reaction (dissociation):
Sr₃(AsO₄)₂(s) → 3Sr²⁺(aq) + AsO₄³⁻(aq).
s(Sr₃(AsO₄)₂) = 0.0650 g/L.
s(Sr₃(AsO₄)₂) = 0.0650 g/L ÷ 540.7 g/mol = 1.2·10⁻⁴ mol/L.
s(Sr²⁺) = 3s(Sr₃(AsO₄)₂).
s(AsO₄³⁻) = 2s(Sr₃(AsO₄)₂).
Ksp = s(Sr²⁺)³ · s(AsO₄³⁻)².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108 · (1.2·10⁻⁴ mol/L)⁵ = 2.69·10⁻¹⁸.
<h3>
Answer:</h3>
6.68 g MgSO₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.965 L
0.0575 M
<u>Step 2: Identify Conversions</u>
Molar Mass of Mg - 24.31 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol
<u>Step 3: Find MgSO₄</u>
- Substitute [M]: 0.0575 M = x / 0.965 L
- Isolate <em>x</em>: 0.055488 mol MgSO₄ = x
- Rewrite: x = 0.055488 mol MgSO₄
<u>Step 4: Convert</u>
<u />
= 6.67959 g MgSO₄
<u>Step 5: Check</u>
<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>
6.67959 g MgSO₄ ≈ 6.68 g MgSO₄
Answer:
It's just asking you to rearrange to equations to get what you want, so no numbers involved it's just teaching you the basics.
Explanation:
Answer:
The correct answer to the following question will be "0.0013%".
Explanation:
The given values are:
Weight of an empty dish = 1.0041 ± 0.0002 g
Weight of dish + sodium chloride (NaCl) = 3.2933 ± 0.0002 g
Weight of NaCl = 2.2892 ± 0.0002 g
Now,
Volume of the solution = 500.00 ± 0.05 ± 0.0002
= 500.00 ± 0.0502 ml
So,
Molarity = 
On putting the values in the above formula, we get
= 
= (
±
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±
)
= (
±
)
Now,
Absolute error = 
=
%