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Nitella [24]
3 years ago
7

The elements chlorine and iodine have similar chemical properties because they _____. Group of answer choices have the same numb

er of stable isotopes are both metals and can easily lose electrons to form compounds None of these have the same number of electrons in their outer energy levels are in the same chemical period
Chemistry
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

Have the same number of electrons in their outer energy levels

Explanation:

Elements in the same group have similar chemical properties because they have the same number of valence electron(s) in their outermost shell.

Chlorine and Iodine have similar chemical properties because they have the same number of valence electron in their outermost shell. This can be seen from their electronic configuration as shown below:

Cl (17) => 1s² 2s²2p⁶ 3s²3p⁵

I (53) => [Kr] 4d¹⁰ 5s²5p⁵

From the above illustration:

Outer shell of Cl (3s²3p⁵) = 2 + 5 = 7 electrons

Outer shell of I (5s²5p⁵) = 2 + 5 = 7 electrons

Since they have the same number of valence electrons, therefore, they will have similar chemical properties.

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Planets reflect sunlight. Most planets are close enough to the sun that they can reflect its light and that is why you can see them. Some planets that are far from the sun do not light up because they have no light to reflect.

I hope this was a satisfying answer. Have a great night!
8 0
3 years ago
Is quartz(SiO2) a substance or mixture?
Illusion [34]
Quartz is a substance because the material has uniform properties throughout and is held together via chemical bonds.
8 0
3 years ago
When 1 mole of carbon is burned, carbon dioxide is produced, and 393 kilojoules (kJ) of energy are released. If this reaction is
EleoNora [17]
The energy of 393 kJ is released as heat.  Then, the container will experience an increase of temperature and, given that it is sealed, also an increase of pressure.

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7 0
3 years ago
Explain why we dissected the eggs that didn't hatch. What was the outcome of our dissection? PLEASE HELP DUE TONIGHT
stiks02 [169]

Answer:

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Explanation:

Hope that helped

5 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
3 years ago
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