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Nitella [24]
3 years ago
7

The elements chlorine and iodine have similar chemical properties because they _____. Group of answer choices have the same numb

er of stable isotopes are both metals and can easily lose electrons to form compounds None of these have the same number of electrons in their outer energy levels are in the same chemical period
Chemistry
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

Have the same number of electrons in their outer energy levels

Explanation:

Elements in the same group have similar chemical properties because they have the same number of valence electron(s) in their outermost shell.

Chlorine and Iodine have similar chemical properties because they have the same number of valence electron in their outermost shell. This can be seen from their electronic configuration as shown below:

Cl (17) => 1s² 2s²2p⁶ 3s²3p⁵

I (53) => [Kr] 4d¹⁰ 5s²5p⁵

From the above illustration:

Outer shell of Cl (3s²3p⁵) = 2 + 5 = 7 electrons

Outer shell of I (5s²5p⁵) = 2 + 5 = 7 electrons

Since they have the same number of valence electrons, therefore, they will have similar chemical properties.

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The three greatest Renaissance painters were:
Oksanka [162]
Leonardo de Vinci, Michelangelo, and Raphael.
4 0
3 years ago
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At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0650 g/l. what is the ksp of this salt at this
Luba_88 [7]
Answer is: Ksp for strontium arsenate is 2.69·10⁻¹⁸.
Balanced chemical reaction (dissociation):
Sr₃(AsO₄)₂(s) → 3Sr²⁺(aq) + AsO₄³⁻(aq).
s(Sr₃(AsO₄)₂) = 0.0650 g/L.
s(Sr₃(AsO₄)₂) = 0.0650 g/L ÷ 540.7 g/mol = 1.2·10⁻⁴ mol/L.
s(Sr²⁺) = 3s(Sr₃(AsO₄)₂).
s(AsO₄³⁻) = 2s(Sr₃(AsO₄)₂).
Ksp = s(Sr²⁺)³ · s(AsO₄³⁻)².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108 · (1.2·10⁻⁴ mol/L)⁵ = 2.69·10⁻¹⁸.
3 0
3 years ago
How many grams of magnesium<br> sulfate (MgSO4) are dissolved in<br> 0.965 L of a 0.0575 M solution?
JulsSmile [24]
<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.965 L

0.0575 M

<u>Step 2: Identify Conversions</u>

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

<u>Step 3: Find MgSO₄</u>

  1. Substitute [M]:                     0.0575 M = x / 0.965 L
  2. Isolate <em>x</em>:                              0.055488 mol MgSO₄ = x
  3. Rewrite:                               x = 0.055488 mol MgSO₄

<u>Step 4: Convert</u>

<u />\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} ) = 6.67959 g MgSO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0
3 years ago
Can anyone help me with these I’m really co fused on what to do it’s for chemistry?
liq [111]

Answer:

It's just asking you to rearrange to equations to get what you want, so no numbers involved it's just teaching you the basics.

Explanation:

3 0
3 years ago
An empty weighing dish has a mass of 1.0041 ± 0.0002 g. After you add dried sodium chloride to the dish, the mass is 3.2933 ± 0.
Maurinko [17]

Answer:

The correct answer to the following question will be "0.0013%".

Explanation:

The given values are:

Weight of an empty dish = 1.0041 ± 0.0002 g

Weight of dish + sodium chloride (NaCl) = 3.2933 ± 0.0002 g

Weight of NaCl = 2.2892 ± 0.0002 g

Now,

Volume of the solution = 500.00 ± 0.05 ± 0.0002

                                      = 500.00 ± 0.0502 ml

So,

Molarity = \frac{W \ NaCl}{M \ NaCl} \times \frac{1000}{Volumes \ of \ solution}

On putting the values in the above formula, we get

             = \frac{(2.2892\addeq +0.0002)}{58.440}\times \frac{1050}{(500.00+0.0502)}

             = (3.917 ± 0.0002) × (2 ± 0.0502)

             = (0.7834 ± .00001004)

Now,

Absolute error = \frac{0.00001004}{0.7834}\times 100

                         = 0.0013%

7 0
3 years ago
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