Question

the front and back sides of a person has an area of 900 square inches each side. what is the total force of the atmosphere pressing on this person from the front side?​

Answer 1

Answer:

$5.9\cdot 10^4 N$

Explanation:

First of all, let's convert the area of the front side of the person into $m^2$:

$A=900 in^2=0.58 m^2$

And the atmospheric pressure is

$p=1.01 \cdot 10^5 Pa$

The force pressing on this person from the front side is

$F=pA$

and substituting the values of the pressure and the area, we find

$F=(1.01 \cdot 10^5 Pa)(0.58 m^2)=58,580 N=5.9\cdot 10^4 N$