Answer:
0.64 J/g°C
Explanation:
Using the formula;
Q = m × c × ∆T
Where;
Q = amount of heat
m = mass (g)
c = specific heat capacity
∆T = change in temperature (°C)
In this case:
Q (water) = - Q (metal)
mc∆T (water) = - mc∆T (metal)
According to the information in this question,
For water; m = 100g, c = 4.18J/g°C, ∆T = (25°C - 20°C)
For metal; m = 50g, c =?, ∆T = (25°C - 90°C)
mc∆T (water) = - mc∆T (metal)
100 × 4.18 × (25°C - 20°C) = - {50 × c × (25°C - 90°C)}
100 × 4.18 × 5 = - {50 × c × -65}
2090 = -{-3250c}
2090 = 3250c
c = 2090/3250
c = 0.643
c = 0.64J/g°C
The velocity after 5 seconds is 50 m/s.
Answer:
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Explanation:
Given;
orbital period of 3 years, P = 3 years
To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.
Kepler's third law;
P² = a³
where;
P is the orbital period
a is the orbital semi-major axis
(3)² = a³
9 = a³
a = ![a = \sqrt[3]{9} \\\\a = 2.08 \ years](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B9%7D%20%5C%5C%5C%5Ca%20%3D%202.08%20%5C%20years)
Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.
The answer is: A 33-Newton force pointing upward.
Answer:
d = 1.07 mile
Explanation:
The rationale for this method is that the speed of light is much greater than the speed of sound, the definition of speed in uniform motion is
v = d / t
d = v t
the speed of sound is worth
v = 343 m / s
Therefore, the speed of sound must be multiplied by time to do this, all the units must be in the same system, as the distance in miles is requested
v = 343 m/s (1mile/1609 m) (3600s/1 h) = 343 (2.24) = 767.4 mile/h
v = 343 m / s (1 mile / 1609 m) = 0.213, mile/ s
If the measured time is t = 5s we multiply it by the speed
we substitute
d = 0.213 5
d = 1.07 mile
If you want to calculate the speed, this method in general is not widely used, since you must know the distance where the lightning occurred, which is relatively complicated.
