Question

a rifle is aimed directly at the bulls eye of a target 75 meters away. if the bullet has a speed of 250 m/s, how far below the bulls eye will the bullet hit

Answer 1

Answer:

Explanation:

Given

Distance of target d=75 m

velocity of bullet v=250 m/s

First taking horizontal motion

as there is no acceleration is horizontal direction therefore $a_x=0$

$d=ut+\frac{1}{2}a_xt^2$

where u=initial velocity

$a_x$=acceleration

t=time

$75=250\times t$

$t=0.3 s$

In this time Vertical distance moved by Bullet is

$y=u_yt+\frac{1}{2}a_yt^2$

here $u_y=0$

$a_y=g=9.8 m/s^2$

$y=\frac{1}{2}\cdot 9.8\cdot (0.3)^2$

$y=0.441 m$