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3 years ago

A 30 kg buzzard is sitting on a cable. The cable is attached to two poles 25

Physics

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

T1 = 675 [N] ; T2 = 707.5 [N]

Explanation:

To solve this problem we must draw a free body diagram, where the bird is located, the posts and distances mentioned.

In the attached image we can see the free body diagram with different forces, angles and distances.

By conducting a distance analysis we can find the angles on both sides of the rope relative to the horizontal.

Then we perform a force analysis on the X-axis and the y-axis in order to find the two equations we need to find the stresses in the cables (T1 & T2)

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A book rests on a wooden table is an example of

kykrilka [37]

Answer:

Static friction

Explanation:

When there is contact between two surfaces and there is no movement, there is static friction. So, if we have a book that rests on a wooden table, we have an example of Static friction, where this force avoids the movement of the book.

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1 year ago

Assessing how well one variable predicts another variable is to blank as detecting cause-effect relationships between different

Reptile [31]

Are you asking about independent and dependent variables?

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3 years ago

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Using calcium’s atomic structure, as shown in the image, what is this element’s atomic number?

ElenaW [278]

Answer:

Atomic number of calcium is 20.

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3 years ago

A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i

attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>

As per Newton's equation of motion, V= U+at
U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>

As per Newton's equation of motion,

V²-U² = 2aS

S= distance covered by the car
So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

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1 year ago

Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 new

Arte-miy333 [17]

The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:
$F=qE=(8.1 \cdot 10^{-9}C)(9.4 \cdot 10^7 N/C)=0.76 N$

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3 years ago

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