Please help with number 18

Please help! I'd really appreciate it :-)

Alexxx [7]

Answer:

0.31429 Amps

Explanation:

Using the "Ohm's Law" we can look for the current (amps) with a formula of I = V/R

Given:

Resistance (Ohm) = 350

Volts = 110

Solution:

I = 110v/350r

I = 0.31429 amps

6 0

3 years ago

What is the unit used to express the power

Deffense [45]

The watt<span> (symbol: W) is a unit of power i hope this helps you</span>

8 0

4 years ago

Find the odd one out radish,potato, beet,carrot.

romanna [79]

Answer:

Potato is not a root whereas the rest of the four items are forms of root.

Potato is a stem.

So, option B is the odd one out

4 0

3 years ago

At the very end of Wagner's series of operas The Ring of Nibelung, Brunnhilde takes the golden ring form the finger of the dead

Blababa [14]

Answer:

a) 404 m² b) apparent height = 7.5 m

Explanation:

This question is about refraction and total internal refraction.

Here I will take refractive index of air and water

$n_{air}=1\\ n_{water}=1.33=4/3$

Now let's look at the diagram I have attached here

At some angle A, the light from the ring (yellow point) under water will be totally internally refracted (B = 90°), which means that rays of light (yellow arrow) that make large enough angle A will not be able to escape from the water. Since we assumed that the ring is a point, there will be a critical cone of angle A with the ring at its apex which traces a circle of radius R on the surface of water, which, beyond this radius, no light could escape.

According to snell's law

$\frac{sin(B)}{sin(A)} = \frac{n_{water}}{n_{air}} = 4/3$

At critical angle B = 90°

$\frac{3)}{4}sin(B) = [tex]\frac{3}{4} sin(90^\circ ) = 0.75 = sin(A)$

Therefore

$A = 48.6^\circ$

With this, we can find the radius of the circle (refer to my diagram)

$h* tan (A) = R\\R =11.3 m$

And with that we can find the area

$A = \pi R^2=404\ m^2$

Additional Problem

For apparent depth from above, we can think that, since we are accustomed to seeing light at the speed of c in air, our brain interpret light from <em>any</em> source to be traveling at c. This causes light that originated under water, which has the speed of

$v_{water} = \frac{c}{n_{water}} = 0.75c$