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Tpy6a [65]
3 years ago
13

How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)? 2LiOH + H2SO4

→ Li2SO4 + 2H2O
Chemistry
2 answers:
den301095 [7]3 years ago
6 0

The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.  

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

The given chemical equation is balanced.  

By using stoichiometry, one can witness the following:  

2 moles of LiOH requires 1 mole of H₂SO₄

So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄


Stels [109]3 years ago
4 0

Answer:

2.3 mol H2SO4

Explanation:

I just took the test ;)

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- Light energy from sun is converted into electrical energy in a solar cell.
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- Chemical energy is converted back into electrical energy at night.
- Electrical energy is converted into light energy from the street lamp.

6 0
3 years ago
When rubbed against a silk cloth, a glass rod loses electrons. How does this affect the charges of the glass rod and the silk cl
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Answer:

Explanation:

The glass rod losses electrons because the silk cloth has a positive charge so it attracts the negative charge of the glass rod.

7 0
3 years ago
Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem
belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

6 0
4 years ago
What type of ion and what charge does sulfur form?
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6 0
3 years ago
Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2
natka813 [3]

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

6 0
2 years ago
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