How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)? 2LiOH + H2SO4

Question

3 years ago

13

→ Li2SO4 + 2H2O

2 answers:

den301095 [7] · Answer 1 · 2022-02-21T00:54:11+03:00

The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

The given chemical equation is balanced.

By using stoichiometry, one can witness the following:

2 moles of LiOH requires 1 mole of H₂SO₄

So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄

Stels [109] · Answer 2 · 2022-02-21T02:04:44+03:00

4 0

Answer:

2.3 mol H2SO4

Explanation:

I just took the test ;)