3......................................
Energy is released as a bond is formed
1) balance the equation
N2 + 3 H2 → 2 NH3
2) change the given grams to moles
(42.5 g N2) / (28.01344 g N2/mol) = 1.5171 mol N2
(10.1 g H2) / (2.015894 g H2/mol) = 5.0102 mol H2
3) compare moles * remember to multiply by the coefficient of the balanced equation
1.5171 moles of N2 would react completely with 1.5171 x (3/1) = 4.5513 moles of H2, but there is more H2 present than that, so H2 is in excess and N2 is the limiting reactant.
4) from the balanced equation moles of limiting reactant to moles produced and then multiply by MW of product
(1.5171 mol N2) x (2 mol NH3 / 1 mol N2) x (17.03056 g NH3/mol) = 51.7 g NH3
5) finally subtract the moles of limiting reactant from moles of excess reactant and multiply by excess reactants MW.
((5.0102 mol H2 initially) - (4.5513 mol H2 reacted)) x (2.015894 g H2/mol) =
0.925 g H2 left over
Answer:
111.03kPa = P₂
Explanation:
Gay Lussac's Law states that the pressure of a gas is directly proportional to the absolute temperature when volume remains constant.
The equation is:
P₁T₂ = P₂T₁
<em>Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.</em>
<em />
P₁ = 85.5kPa
T₂ = 127°C + 273.15 = 400.15K
P₂ = ?
T₁ = 35°C + 273.15 = 308.15K
P₁T₂ = P₂T₁
85.5kPa*400.15K = P₂*308.15K
<h3>111.03kPa = P₂</h3>