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2 years ago

23)

Chemistry

2 answers:

Tema [17]2 years ago

4 0

Ammonia I think (NH3)

eduard2 years ago

3 0

Answer:

Its C) HClO4

Explanation:

I just took the quiz and it was right :))

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Landfills are one source of CO2. As garbage decomposes, it releases CO2 into the air. Can you think of at least

Margaret [11]

Answer:

Recycling and reuse of materials

Explanation:

One of the greatest problems facing the human population is the problem of solid waste disposal. The menace of solid waste disposal has led to the idea of landfills. Land fills are depressions on the earth surface prepared for the purpose of solid waste disposal.

The most important approach towards solid waste disposal is the idea of recycling of materials. A material can be collected after use and processed into the same material or serve as a precursor in another manufacturing process. This means that no waste is generated as the materials which are supposed to be disposed of as solid waste are processed into other useful materials. This will reduce the volume of solid wastes generated that may need to be disposed in a landfill.

7 0

2 years ago

Isotopes that decay with a nuclear break-up and emit a significant amount of energy are said to be ________.

podryga [215]

Answer to this is Radioactive isotopes.

Isotopes are the species of the same element having different atomic masses that means the number of protons remains the same but number of neutrons do differ. For example $_{1}^{2}\textrm{H}$ and $_{1}^{3}\textrm{H}$ are the two isotopes of Hydrogen ( $_{1}^{1}\textrm{H}$ ).

Radioactive isotopes are the isotopes which release some kind of energy in the form of alpha particles, beta particles or gamma radiation. Examples of each of the decay processes are :

Alpha Decay: In this decay one alpha particle having atomic mass 4 and atomic number 2 or we can say a He molecule will come out. $_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_{2}^{4}\alpha$

Beta Decay: In this decay a $\beta$ particle is emitted increasing the atomic number of the reactant by 1 unit.

$_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^{0}\beta$

Gamma Radiation: In this type of reaction only radiation is emitted out which does not change the original molecule.

$_{Z}^{A}\textrm{X}\rightarrow _{Z}^{A}\textrm{X}+\gamma\text{ radiation}$

3 0

2 years ago

When the metal was placed in the calorimeter, its temperature dropped to the equilibrium temperature. Calculate the change in te

MAVERICK [17]

Answer:

1st one= -79.6

2nd one= -80

3rd one= -81.2

Explanation:

Good luck!

5 0

2 years ago

Read 2 more answers

When 1. 0 l of 0. 00010 m naoh and 1. 0 l of 0. 0014 m mgso4 are mixed, would a precipitate be formed? show work

koban [17]

When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.

<h3>What is a precipitate?</h3>

The precipitate is the solid concentration of a substance that is collected over a solution.

First, we determine the concentration of magnesium and hydroxide

(Mg2+) = 7.00 × 10⁻⁴

(OH−) = 5.00 × 10⁻⁵

Now, we calculate the solubility quotient

Qc = (Mg2+) (OH−) ²

Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²

Qc = 1.75 x 10⁻¹²

The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.

Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.

To learn more about precipitate, refer to the below link:

brainly.com/question/16950193

#SPJ4

5 0

1 year ago

Which is the correct number of moles of NO that is produced from 13.2 moles of oxygen

Oksanka [162]

<h3>Answer:</h3>

10.6 mol NO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O

[Given] 13.2 mol O₂

<u>Step 2: Identify Conversions</u>

[RxN] 5 mol O₂ → 4 mol NO

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 13.2 \ mol \ O_2(\frac{4 \ mol \ NO}{5 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 10.56 \ mol \ NO$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

10.56 mol NO ≈ 10.6 mol NO

5 0

2 years ago