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shtirl [24]
3 years ago
6

A kite is 100m above the ground. If there are 200m of string out, what is the angle between the string and the horizontal? (Assu

me that the string is perfectly straight.)
Physics
1 answer:
belka [17]3 years ago
3 0

Answer:

the answer is 30°

Explanation:

due to:

sin law of sines

\frac{sin 90}{200} =\frac{sin\beta }{100}\\arcsin(100\frac{sin90}{200} )= 30°

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WHERE IS THE HYPOTHESIS IN THIS PASSAGE?
yuradex [85]

Answer:

pretty sure for this one, "if the density affected the liquid's ability to retain heat."

Explanation:

a hypothesis should be in "if, then, because.." format, and while this bit of the passage doesnt include all three, it does include one! that bit of the passage would be an incomplete hypothesis.

4 0
3 years ago
Timed please hurry
vladimir1956 [14]
The answer is D. disorganized
5 0
3 years ago
Read 2 more answers
Please help me!!!!!!!! it's due soon!!!!!!!!!!!!! NO LINK!!!!!!!!!
maria [59]
.75(m/s)^2


Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide

7 0
3 years ago
KI + Cl2 ---&gt; KCl + I2<br> Balance the single replacement chemical reaction.
snow_lady [41]

Answer:

2KI   +  Cl₂   →   2KCl     +    I₂

Explanation:

The reaction equation is given as:

        KI   +  Cl₂   →    KCl     +    I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

        aKI   +  bCl₂   →    cKCl     +    dI₂

 Conserving K : a = c

                     I :  a  = 2d

                   Cl : 2b = c  

 Now let a = 1, c  = 1 , d  = \frac{1}{2}, b   = \frac{1}{2}, ;

   Multiply through by 2;

             a  = 2, b = 1 , c = 2, d  = 1

 

            2KI   +  Cl₂   →   2KCl     +    I₂

 

5 0
3 years ago
49W
Nikolay [14]

Answer:

16

Explanation:

The magnitude of the electrostatic force between two charged particles is given by

F=\frac{kq_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the charges of the two particles

r is the separation between the particles

In this problem, the initial force between the particles is F.

Later, the distance between the two particles is increased by four, so

r' = 4r

So, the new force between the particles will be

F'=\frac{kq_1 q_2}{(4r)^2}=\frac{kq_1 q_2}{16r^2}=\frac{1}{16}F

So, the new force decreases by a factor of 16.

4 0
3 years ago
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