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Anarel [89]
3 years ago
15

None of the given molecules display much solubility in water at room temperature. However, two of the molecules display apprecia

ble solubility in boiling water. salicylic acid 2-naphthol acetaminophen Based on its structure, which molecule will be the least soluble in hot water?
Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
5 0

2-naphthol, based on its structure will be least soluble in water.

2-Naphthol, or β-naphthol, is a fluorescent, colorless (or occasionally yellow) crystalline solid with the formula C10H7OH. It is an isomer of 1-naphthol, differing by the location of the hydroxyl group on the naphthalene ring. The naphthols are naphthalene homologues of phenol, but more reactive. Both isomers are soluble in simple alcohols, ethers, and chloroform. 2-Naphthol is a widely used intermediate for the production of dyes and other compounds.

You might be interested in
The following balanced equation shows the formation of ethane (C2H6).
almond37 [142]

Answer:

C

Explanation:

Well, we can see from the equation that hydrogen gas and ethane are in a 2:1 ratio based on their mole coefficients.

You need 2 mol H2 to make 1 mol C2H6. So that means you need 2*13.78 mol H2 to make 13.78 mol C2H6!

2*13.78 = 27.56 mol

C is correct.

4 0
3 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
Which of the following is the valence elec- tronic structure for a halogen? 1. n s1 2. n s2 3. n s2 n d10 4. n s2 n p5 5. n s2 n
Arturiano [62]

Answer: option 4. ns² np⁵

Explanation:

The <em>valence electronic structure</em> of the compounds is the distribution of the valence electrons, i.e. the outermost electrons of the atoms.

The distribution of the electrons in the atomic orbitals is named electron configuration.

Each element has a proper electron configuration which is determined according to a series of rules: lowest orbital energy, Pauli's exclusion principle and Hund's rule.

The valence electronic structure of the atoms is related with the period (column of the periodic table) to which the element belongs.

Each period has a characteristic <em>valence structure</em> (number and location of the outermost electrons). It is this structure what conferes the elements of a same period (column in the periodic table) their similar chemical properties.

This table summarizes the <em>valence eletronic structure </em>of the representative elements:

<u>Period (column)    name         number of valence eletrons    Structure</u>

1                        Alkali metals                             1                             ns¹

2                       Alkaline earth metals               2                            ns²

13                                                                        3                            ns² np¹

14                                                                        4                            ns² np²                                          

15                      Pnictogens                               5                             ns² np³                                                                                        

16                      Chalcogens                              6                             ns² np⁴

17                      Halogens                                  7                             ns² np⁵

18                      Noble gases                             8                            ns² np⁶

There you can see that the <em>halogens</em> belong to the period 17, have 7 valence electrons, and their<em> valence electrons are have the structure ns² np⁵.</em>

This is the specific valence electronic structure for the first five halogens:

<u>Halogen      atomic number      row (n)   period   valence electronic structure</u>

Fluor               9                             2            15                  2s² 2p⁵

Chlorine        17                             3            15                  3s² 3p⁵

Bromine        35                            4            15                  4s² 4p⁵

Iodine            53                            5            15                  5s² 5p⁵

Astatine        85                            6             15                 6s² 6p⁵

There you see the common <em>structre ns² np⁵.</em>

8 0
4 years ago
Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.
denpristay [2]

<u>Answer:</u>

<u>For a:</u> The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

<u>For b:</u> The mass of methane gas produced will be 10.384 g.

<u>Explanation:</u>

For the given chemical reaction:

2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ

  • <u>For a:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = \frac{252.8}{2}\times 0.749=94.6736kJ

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

  • <u>For b:</u>

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = \frac{2}{252.8}\times 82.1=0.649mol of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g

Hence, the mass of methane gas produced will be 10.384 g.

7 0
4 years ago
In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as
aalyn [17]

Answer:

Single displacement reaction.

Explanation:

Hello!!

In this case, since the reaction between silver nitrate and copper metal is:

2AgNO_3(aq)+Cu(s)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq)

As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.

Therefore, this is a single displacement reaction, because the the lonely copper displaced the silver.

Best regards!

7 0
3 years ago
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