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Gemiola [76]
3 years ago
5

A sample of propane, C3H8, contains 15.5 moles of carbon atoms. How many total moles of atoms does the sample contain?

Chemistry
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

H = 41.3 mol H; Atoms = 56.8 mol

Explanation:

A molecule of propane contains eight atoms of H for every 3 atoms of C or <em>8 mol H atoms for every 3 mol C atoms</em>.

∴ \text{Moles of H atoms} = \text{15.5 mol C atoms} \times \frac{\text{8 mol H atoms }}{\text{3 mol C atoms }} = \text{41.3 mol H atoms}

Total atoms = 15.5 mol C atoms + 41.3 mol H atoms = 56.8 mol atoms

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M1V1 = M2V2
M1 = 3.000 M
V1 = 0.8000 L
M2 = ?
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M2 = M1V1/V2 = (3.000 M)(0.8000 L)/(2.00 L) = 1.20 M
5 0
2 years ago
Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re
blondinia [14]
M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x <span> 0.0512 => 0.0057856 moles of NaOH

mole ratio:

</span><span>HCl + NaOH = NaCl + H2O
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1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- </span><span> 0.0057856 moles NaOH
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(moles HCl ) = <span> 0.0057856 x 1 / 1
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= <span> 0.0057856 moles of HCl
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M ( HCl ) = n / V

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= 0.227 M

Answer A

hope this helps!

4 0
3 years ago
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Listed below are possible solutes. In your possession is a beaker with 500 milliliters of water. You want to make an aqueous sol
slavikrds [6]

Answer: I & III

Explanation:  Solutes are the substances which are minimum in quantity and which is required to dissolve in the solvent (which is larger in quantity) in order to make a solution.

In the asked question, it is given that the water is the solvent and from the given solutes we have to pick which would make an aqueous solution with the highest concentration of solute possible.

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Fr33 points ;p have a good day everyone
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Answer:

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