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liq [111]
3 years ago
11

Water is the working fluid in an ideal regenerative Rankine cycle with one open feedwater heater. Superheated vapor enters the f

irst-stage turbine at 16MPa,560∘C, and the condenser pressure is 8 kPa. The mass flow rate of steam entering the first-stage turbine is 120 kg/s. Steam expands through the first-stage turbine to 1 MPa where some of the steam is extracted and diverted to an open feedwater heater operating at 1 MPa. The remainder expands through the second-stage turbine to the condenser pressure of 8 kPa. Saturated liquid exits the feedwater heater at 1 MPa. Determine
a. the net power developed, in kW.
b. the rate of heat transfer to the steam passing through the boiler, in kW.
c. the thermal efficiency.
d. the mass flow rate of condenser cooling water, in kg/s, if the cooling water undergoes a temperature increase of 18∘C with negligible pressure change in passing through the condenser.

Engineering
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

a) The net powered developed will be 145715 KW.

b) The rate of Heat Transfer to the steam passing through the boiler will be 326340 KW.

c) The thermal efficiency will be 0.45.

d) The mass flow rate will be 884.09 kg/s.

Explanation:

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3 years ago
A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1
ella [17]

Answer:

a)

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0
2 years ago
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Answer:

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Explanation:

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7 0
2 years ago
What is the difference between a discrete and continuous system?
Serjik [45]

Answer:Discrete system are those system which change the state at the discrete point of time and continuous system are those which have state change at continuous period of time.

Explanation:

  • The major difference between discrete and continuous system is that, discrete system has state change over a discontinuous time period whereas the change of state in continuous system is over a continuous time period .
  • Variations can be found in the discrete system signal but  in continuous system variation cannot be found input and output signal.
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       Discrete system:-employees reporting at office at different time like

       9:10am, 9:15am etc              

       <u> Continuous system</u>:-the water flow over a dam in particular quantity                    

7 0
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Water, initially saturated vapor at 4 bar, fills a closed, rigid container. The water is heated until its temperature is 440°C.
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Answer:

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Explanation:

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