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Sliva [168]
3 years ago
6

When substances react chemically to create a new substance, will that new substance have the same physical and chemical properti

es as the initial substance? Explain your answer.
Chemistry
1 answer:
Makovka662 [10]3 years ago
8 0

Answer:

When a chemical reaction occur, new substances are formed. The physical and chemical properties of new substances are different from initial substance.

Explanation:

Chemical change:

The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.

These changes are irreversible.

These changes occur due to chemical reactions.

These may not be observed with naked eye.

Examples:

Combustion of fuel or wood: that oil or wood convert into energy, CO2 and ash in case of wood .

Boiling of egg: that change the chemical composition of protein in the egg.

Physical change:

The changes that occur only due to change in shape or form but their chemical or internal composition remain unchanged.

These changes were reversible.

They have same chemical property.

These changes can be observed with naked eye.

Examples:

Water converting to Ice.

Water converting to gas.

In this water molecule remain the same only they rearrange themselves that change its state of mater not composition.

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The mass of an object is 13.76 g. the volume of the object is 2.83 ml. what is the density of the object to the correct number o
Firlakuza [10]

Answer:

D ≈ 4.86 g/mL

Explanation:

Density = Mass over Volume

D = m/V

Step 1: Define variables

m = 13.76 g

V = 2.83 mL

D = unknown

Step 2: Substitute and Evaluate for Density

D = 13.76 g/2.83 mL

D = 4.8621908127208480565371024734982 g/mL

Step 3: Simplify

We are given 3 sig figs.

4.8621908127208480565371024734982 g/mL ≈ 4.86 g/mL

7 0
3 years ago
How many moles are in 3.01*10^23 atoms of Mg
Basile [38]
1 mole ------------ 6.02x10²³ atoms
? moles ----------- 3.01x10²³ atoms

moles = ( 3.01x10²³ ) x 1 / 6.02x10²³

=> 0.5 moles Mg
7 0
4 years ago
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL from C12H22O11
ser-zykov [4K]

Answer:

\boxed{\text{3.4 g}}

Explanation:

Step 1. Calculate the moles of C₁₂H₂₂O₁₁

\text{n = 0.100 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}}=\text{0.100 mol}

Step 2. Calculate the mass of C₁₂H₂₂O₁₁

\text{m = 0.100 mol} \times \dfrac{\text{342.30 g}}{\text{1 mol}} = \text{3.4 g}\\\\\text{The mass of sucrose needed is }\boxed{\textbf{3.4 g}}

6 0
4 years ago
Which of the following shows a coefficient?
rosijanka [135]

Answer:

my answer is b oti d I am not sure

6 0
3 years ago
30. A solid sample contains only CaCO3, and MgCO3.
lutik1710 [3]

Answer:

Explanation:

Step 1

The mass percent of MgCO3 in the original mixture is calculated as shown,

Step 2

Masses of MgCO3 and CaCO3 is 24g; Moles of carbon dioxide produced from Magnesium carbonate  and Calcium carbonate are.

Step 3

Adding and equating the moles of Carbon dioxide results in,

Step 4

Percent mass of MgCO3 in the sample is calculated as,

8 0
3 years ago
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