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AlexFokin [52]
3 years ago
9

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the r

esistance of the circuit in the absence of the 580 resistor.
Physics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

1160 ohm

Explanation:

We are given that

R'=580 ohm

Current=3 I

We have to find the resistance of the circuit.

Let R be the resistance of circuit.

In parallel

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}

Using the formula

\frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}

R_{eq}=\frac{580R}{580+R}

In parallel combination,Potential difference across each resistance remains same.

V=IR

Using the formula

IR=3IR_{eq}

IR=3I\times \frac{580R}{580+R}

580+R=3\times 580=1740

R=1740-580=1160\Omega

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