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AlexFokin [52]
3 years ago
9

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the r

esistance of the circuit in the absence of the 580 resistor.
Physics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

1160 ohm

Explanation:

We are given that

R'=580 ohm

Current=3 I

We have to find the resistance of the circuit.

Let R be the resistance of circuit.

In parallel

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}

Using the formula

\frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}

R_{eq}=\frac{580R}{580+R}

In parallel combination,Potential difference across each resistance remains same.

V=IR

Using the formula

IR=3IR_{eq}

IR=3I\times \frac{580R}{580+R}

580+R=3\times 580=1740

R=1740-580=1160\Omega

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Which of the following statements about electric field lines associated with electric charges is false? Electric field lines can
Tcecarenko [31]

Answer:

The false statement is 'Electric field lines form closed loops'.

Explanation:

  • Electric field lines originate from positive end and terminates at negative end,i.e., field lines are inward in direction to the negative charges and outward from the positive charges.
  • These lines when close together represents high intensity and when far apart shows low intensity of the field.
  • These lines do not intersect, as the tangent drawn on these lines provides us with the field direction and intersection of these lines means two field directions which is not possible.
  • These lines unlike magnetic field lines do not form closed loops as they do not turn around but originate at positive end and terminates at negative end which ensures no loop formation.
8 0
3 years ago
A flat disk of radius 0.50 m is oriented so that the plane of the disk makes an angle of 30 degrees with a uniform electric fiel
nexus9112 [7]

Answer:

The electric flux is 280\ \rm N.m^2/C

Explanation:

Given:

  • Radius of the disc R=0.50 m
  • Angle made by disk with the horizontal \theta=30^\circ
  • Magnitude of the electric Field E=713.0\ \rm N/C

The flux of the Electric Field E due to the are dA in space can be found out by using Gauss Law which is as follows

\phi=\int E.dA

where

  • \phi is the total Electric Flux
  • E is the Electric Field
  • dA is the Area through which the electric flux is to be calculated.

Now according to question we have

=EA\cos\theta \\=713\times 3.14\times 0.5^2 \times \cos60^\circ\\=280\ \rm N.m^2/C

Hence the electric flux is calculated.

8 0
3 years ago
What is the size of earth?
shtirl [24]

Answer:

Google it

Explanation:

Best if you use google

4 0
3 years ago
Read 2 more answers
Plz help 20 points!!
vazorg [7]

Answer:

1-d

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3-e

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This is the correct sequence

5 0
2 years ago
g At some point the road makes a right turn with a radius of 117 m. If the posted speed limit along this part of the highway is
user100 [1]

Answer:

Ф = 28.9°

Explanation:

given:

radius (r) = 117m

velocity (v) = 25.1 m/s

required: angle Ф

Ф = inv tan (v² / (r * g))      we know that g = 9.8

Ф = inv tan (25.1² / (117 * 9.8))

Ф = 28.9°

6 0
4 years ago
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