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Svetllana [295]
3 years ago
13

A 17.5-kg block is dragged over a rough, horizontal surface by a 75-N force acting at 21° above the horizontal. The block is dis

placed 5.7 m, and the coefficient of kinetic friction is 0.150.
Requried:
a. Find the work done on the block by the 75-N force.
b. Find the work done on the block by the normal force.
c. Find the work done on the block by the gravitational force.
d. What is the increase in internal energy of the block-surface system due to friction?
e. Find the total change in the block's kinetic energy.

Physics
1 answer:
pogonyaev3 years ago
5 0

Answer:

Explanation:

given

m= 17.5kg

F= 75N

d= 5.7m

∪=0.150

θ= 21°

a. W = Fcos θ × d

75cos21° ×5.7

=399.106J

b. normal force is zero. 0 Joules

cos 90°=0

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Answer:

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Explanation:

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3 years ago
A stone is thrown vertically upward with a speed of 18.0 . (a)How fast is it moving when it reaches a height of 11.0 ? (b)How lo
aliina [53]
For the first part, we are looking for Vf when dy=11.0
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<span>Vf = 10.4 m/s your answer is correct. 

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A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motio
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Answer:

3.25 seconds

Explanation:

It is given that,

A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :

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For the given condition, the equation becomes:

h=-16t^2+50t+7

When it hits the ground, h = 0

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-16t^2+50t+7=0

It is a quadratic equation, we find the value of t,

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