3 years ago

Do not discharge wastewater into storm sewers because they flow directly into local surface waters. A. true B. false

Engineering

1 answer:

enot [183]3 years ago

3 0

Answer:

True

Explanation:

Wastewater should never be discharged into storm sewers. Storm sewers are constructed to store rainwater.

Rainwater passes through storm sewers to the nearest underground water resource if the wastewater discharge into storm sewers, then they will also pollute the ground water, so usually the dirty water is not put in the storm sewers.

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Steam at a pressure of 100 bar and temperature of 600 °C enters an adiabatic nozzle with a velocity of 35 m/s. It leaves the noz

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Answer:

Exit velocity $V_2=1472.2$ m/s.

Explanation:

Given:

At inlet:

$P_1=100 bar,T_=600°C,V_1=35m/s$

Properties of steam at 100 bar and 600°C

$h_1=3624.7\frac{KJ}{Kg}$

At exit:Lets take exit velocity $V_2$

We know that if we know only one property inside the dome then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of nozzle is 0.85 and pressure P=80 bar.So from steam table we can find the other properties.

Properties of saturated steam at 80 bar

$h_f= 1316.61\frac{KJ}{Kg} ,h_g= 2757.8\frac{KJ}{Kg}$

So the enthalpy of steam at the exit of turbine

$h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}$

$h_2=1316.61+0.85(2757.8-1316.61)\frac{KJ}{Kg}$

$h_2=2541.62\frac{KJ}{Kg}$

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$h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w$

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$V_2=1472.2$ m/s

So Exit velocity $V_2=1472.2$ m/s.

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