A standing wave is established on a string that is fixed at both ends. If the string is vibrating at its fundamental frequency,
1 answer:
The concept related to solving the problem is called Standing Waves: This property relates to how, through a chain that is fixed at both ends, it has a fundamental frequency that relates the wavelength of a standing wave to the length of rope.
In other words, if we take a wave that travels in a direction on the rope from one direction, it will immediately tend to return but in the opposite direction. When having two waves traveling in the opposite direction, it is necessary to take into account that during the vibration two reflections are generated on each side. This concept sometimes called constructive interference results in a wave reflection of the type,
Where n is a positive integer,
λ is the wavelength
L is the length of the chain.
In this way it is possible to appreciate that <em>the length of the string is equal to half of a wavelength.</em>
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Answer:
140 J
Explanation:
From the the question, the mass of the man =70.0 kg and the speed at which the man is walking =2.0 m/s.
where K.E = the kinetic energy, m=mass and v= speed.
By substitution,
Hence the kinetic energy of the man is 140J
Answer:
2.85 rad/s
Explanation:
5 cm = 0.05 m
20 g = 0.02 kg
When dropping the 2nd object at a distance of 0.05 m from the center of mass, its corrected moments of inertia is:
So the total moment of inertia of the system of 2 objects after the drop is:
From here we can apply the law of angular momentum conservation to calculate the post angular speed