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OLga [1]
3 years ago
13

A standing wave is established on a string that is fixed at both ends. If the string is vibrating at its fundamental frequency,

how is the length of the string related to the wavelength of the standing wave?
Physics
1 answer:
Alisiya [41]3 years ago
7 0

The concept related to solving the problem is called Standing Waves: This property relates to how, through a chain that is fixed at both ends, it has a fundamental frequency that relates the wavelength of a standing wave to the length of rope.

In other words, if we take a wave that travels in a direction on the rope from one direction, it will immediately tend to return but in the opposite direction. When having two waves traveling in the opposite direction, it is necessary to take into account that during the vibration two reflections are generated on each side. This concept sometimes called constructive interference results in a wave reflection of the type,

\frac {n} {\lambda 2} = L

Where n is a positive integer,

λ is the wavelength

L is the length of the chain.

In this way it is possible to appreciate that <em>the length of the string is equal to half of a wavelength.</em>

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A car drives off a cliff next to a river at a speed of 30 m/s and lands on the bank on theother side. The road above the cliff i
dezoksy [38]

Answer:1.301 s

Explanation:

Given

Initial Velocity(u)=30 m/s

Height of cliff=8.3 m

Time taken to cover 8.3 m

h=ut+\frac{at^2}{2}

here Initial vertical velocity is 0

8.3=\frac{gt^2}{2}

t^2=1.69

t=1.301 s

Horizontal distance

R=u\times t

R=30\times 1.301=39.04 m

7 0
3 years ago
A spinning ice skater will speed up if he brings his arms close to his body. Which of the following statements explains this phe
xxMikexx [17]
A. Angular momentum is always conserved would be the correct answer.

This is because like linear momentum (mvmv), angular momentum (r×mvr×mv) is a conserved quantity, where rr is the vector from the center of rotation. For a skater holding a static pose, for each particle making up her body, the contribution in magnitude to the total angular momentum is given by mirivimirivi. Thus bringing in her arms reduces riri for those particles. In order to conserve angular momentum, there is then an increase in the angular velocity.

hope this helps!
7 0
3 years ago
Read 2 more answers
Please help ASAP!!
bixtya [17]

There is kinetic energy when it is sitting at the top, then as it goes towards the bottom, the kinetic energy is transformed into potential energy.

6 0
3 years ago
A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Ne
Furkat [3]

Answer:

the frequency of this mode of vibration is 138.87 Hz

Explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

F_n = \frac{n}{2L} \sqrt{\frac{T}{\mu} } \\\\F_2 = \frac{2}{2\times 1} \sqrt{\frac{27}{0.0014} }\\\\F_2 = 138.87 \ Hz

Therefore, the frequency of this mode of vibration is 138.87 Hz

7 0
3 years ago
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
VARVARA [1.3K]

Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

d = 3.48 \times 10^{-4} m

Part c)

\theta = 0.311 degree

Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

\lambda = 630 nm

now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

y_n = \frac{n\lambda L}{d}

so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

n = 3

L = 1.4 m

0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})

\theta = 0.311 degree

8 0
3 years ago
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