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3 years ago

An electromagnetic wave has an electric field with a peak value of 250 n/c. what is the average intensity of the wave?

1 answer:

3 0

The amplitude of the electric field of the wave in the problem is $E=250 N/C$ .

The average intensity of the wave is related to the amplitude of the electric field by the equation
$I= \frac{1}{2} c \epsilon_0 E^2$
where I is the intensity, c is the speed of light and $\epsilon_0$ is the electric vacuum permittivity. By using E=250 N/C, we can find the average intensity of the wave:
$I= \frac{1}{2}(3 \cdot 10^8 m/s)(8.85 \cdot 10^{-12} F/m)(250 N/C)^2=83.0 W/m^2$

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Answer:

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The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.

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