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White raven [17]
3 years ago
13

The bar graph shows the population of male and female deer in a forest, measured in 10-year intervals. According to the graph, w

hich of these statements is true about the trends?

Physics
2 answers:
saul85 [17]3 years ago
4 0

Answer: option D. the ratio of the population of male deer is not constant.


Explanation:


The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.


These features are remarkable:


  • The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.

        This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.


  • The population of female deer (purple or brown bars) decreases every decade.

        This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.


  • The populations never are equal, hence this discards the option C.

  • Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
SVEN [57.7K]3 years ago
4 0

Answer:

The answer is D

Explanation:

I got it right

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200 kgm/s

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3. A cat pushes a 0.25-kg toy with a net force of 8 N. According to Newton's second
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\\ \sf{:}\!\implies F=ma

\\ \sf{:}\!\implies Acceleration=\dfrac{F}{m}

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How much potintial energy is in a closed system where the height of the object is 2 m, and the mass is 10 kg?
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Read 2 more answers
Choose the scenario in which the sound frequency of the waves is higher.
mrs_skeptik [129]

Answer:

B) the sound source moves towards you at 100 m/sec

Explanation:

The Dopper Effect is a phenomenon that occur when there is relative motion between an observer and a source of a wave. When this situation occurs, there is an apparent shift in frequency of the wave, as observed by the observer.

The apparent frequency observed by the observer is given by

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the original frequency of the wave

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if moving towards the source of the wave, negative otherwise)

v_s is the velocity of the source (negative if moving towards from the observer, positive otherwise)

In this problem, we want to find the scenario in which the sound frequency is higher.

We see that in all 4 scenarios, the sound source is moving: this means we have to find the scenario in which the denominator of the equation is smaller.

First of all, we notice the sound source moves towards the observer, v_s is negative, so the denominator is higher: this means that the correct option must be either A or B.

Also, we notice that since v_s is negative, a value larger in magnitude will mean a smaller denominator: therefore, the correct answer will be

B) the sound source moves towards you at 100 m/sec

Since this situation will make the denominator of the formula the smallest possible.

5 0
2 years ago
At a picnic, there is a contest in which hoses are used to shoot water at a beach ball from three different directions. As a res
hram777 [196]

Answer:

F₃ = 122.88 N

θ₃ = 20.63°

Explanation:

First we find the components of F₁:

For x-component:

F₁ₓ = F₁ Cos θ₁

F₁ₓ = (50 N) Cos 60°

F₁ₓ = 25 N

For y-component:

F₁y = F₁ Sin θ₁

F₁y = (50 N) Sin 60°

F₁y = 43.3 N

Now, for F₂. As, F₂ acts along x-axis. Therefore, its y-component will be zero and its x-xomponent will be equal to the magnitude of force itself:

F₂ₓ = F₂ = 90 N

F₂y = 0 N

Now, for the resultant force on ball to be zero, the sum of x-components of the forces and the sum of the y-component of the forces must also be equal to zero:

F₁ₓ + F₂ₓ + F₃ₓ = 0 N

25 N + 90 N + F₃ₓ = 0 N

F₃ₓ = - 115 N

for y-components:

F₁y + F₂y + F₃y = 0 N

43.3 N + 0 N + F₃y = 0 N

F₃y = - 43.3 N

Now, the magnitude of F₃ can be found as:

F₃ = √F₃ₓ² + F₃y²

F₃ = √[(- 115 N)² + (- 43.3 N)²]

<u>F₃ = 122.88 N</u>

and the direction is given as:

θ₃ = tan⁻¹(F₃y/F₃ₓ) = tan⁻¹(-43.3 N/-115 N)

<u>θ₃ = 20.63°</u>

7 0
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