1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
4 years ago
13

The bar graph shows the population of male and female deer in a forest, measured in 10-year intervals. According to the graph, w

hich of these statements is true about the trends?

Physics
2 answers:
saul85 [17]4 years ago
4 0

Answer: option D. the ratio of the population of male deer is not constant.


Explanation:


The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.


These features are remarkable:


  • The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.

        This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.


  • The population of female deer (purple or brown bars) decreases every decade.

        This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.


  • The populations never are equal, hence this discards the option C.

  • Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
SVEN [57.7K]4 years ago
4 0

Answer:

The answer is D

Explanation:

I got it right

You might be interested in
Three identical very dense masses of 7500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,
sukhopar [10]

Answer:

0.00354 (N)

Explanation:

Convert to metric system:

x_1 = -100 cm = 1 m

x_2 = 420 cm = 4.2 m

Formula for gravitational force:

F_g = G\frac{mM}{s^2}

where s is the distance between 2 bodies masses m and M

Substitute the number to the formula above and since the 2 forces are acting in opposite direction, the total net gravitational force on the mass of origin be:

F_g = F_{g1} - F_{g2}

F_g = G\frac{m_1M}{x_1^2} - G\frac{m_2M}{x_2^2}

F_g = GM(\frac{m_1}{x_1^2} - \frac{m_2}{x_2^2})

F_g = 6.67*10^{-11} * 7500 (\frac{7500}{1^2} - \frac{7500}{4.2^2})

F_g = 5*10^{-7}(7500 - 425.17)

F_g = 5*10^{-7} * 7074.83

F_g = 0.00354 (N)

5 0
3 years ago
Tropism to stimuli could be slow at fast but all plants respond to __?
FromTheMoon [43]
HI MY NAME IS GUNTA!!!
5 0
4 years ago
What type of image is formed by a lens if m = -2.0?
MA_775_DIABLO [31]
A real image is smaller than the object
7 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 59 m high. The ball strikes the ground at a point 65 m horizontally awa
Ugo [173]

Answer:

Explanation:

We are looking for final velocity. Since the ball is thrown horizontally, there is no upwards velocity, so the y dimension here is only useful to us for finding how long the ball was in the air. In the y dimension, here's what we know:

a = -9.8 m/s/s

Δx = -59 m

v_0=0 (again, initial upwards velocity is 0 because the ball was thrown horizontally)

We can put all that together in the equation:

Δx = v_0t+\frac{1}{2}at^2 and filling in:

-59=0t+\frac{1}{2}(-9.8)t^2 which simplifies to

-59=\frac{1}{2}(-9.8)t^2 and solving for t:

t=\sqrt{\frac{2(-59)}{-9.8} } and

t = 3.5 sec

Now we can use that time in the d = rt equation, which is all we need for the horizontal dimension (I'll show you why in just a second). In the horizontal dimension, here's what we know:

a = 0 m/s/s

Δx = 65 m

t = 3.5 sec

Putting that all together in our one-dimensional equation for displacement:

Δx = v_0t+\frac{1}{2}at^2 and acceleration is 0, we can simplify that down to

Δx = v_0t which is the exact same thing as d = rt where r is the velocity we are looking for. Filling in:

65 = v(3.5) so

v = 18.6 m/s

That's the velocity with which the ball strikes the ground.

5 0
3 years ago
How many electrons must be transferred from an object to produce a charge of 1.15 c? (express your answer to three significant f
Darina [25.2K]
<span>To produce a charge of 1.15 Coulombs in an object, we need to transfer = 1.15/(charge on an electron) number of electrons

   As we know that, total charge on an electron = 1.60217662 Ă— 10 ^-19 coulombs
    Hence, number of electrons required to move = 1.15/(1.60217662 Ă— 10 ^-19) = 0.71777 x 10^19 electrons, i.e. 7.17 x 10^18 electrons upto 3 significant figures</span>
6 0
4 years ago
Other questions:
  • How can you break open a coconut without ANY tools, only your hands, that means no rocks, no hammers, no special tools, and don'
    13·1 answer
  • Polarized light passes through a polarizer. If the electric vector of the polarized light is horizontal what, in terms of the in
    11·1 answer
  • Why life is often referred to as carbon based
    15·1 answer
  • It has affected how we communicate, made us think we have to live perfect lives, caused drama, and BULLYING idea.
    5·1 answer
  • What happens to the heat energy when you decrease the length of an object​
    10·2 answers
  • Describe how wet and dry barometers work
    11·1 answer
  • When a car climbs a hill, it has only potential energy<br> True or false ​
    12·2 answers
  • Kinetic vs potential energy
    6·1 answer
  • What is the mass of a man who accelerates 4 m/s2 under the action of a 300 N net force?
    15·1 answer
  • Someone please help me understand this question!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!