Mass of calcium carbonate (in grams) can be dissolved by 4.1 g of Hcl is 5.62g.
<h3>What is balanced equation?</h3>
A balanced equation is one for a chemical reaction in which the overall charge and the number of atoms for each component are the same for both the reactants and the products. In other words, the mass and charge of both sides of the reaction are equal.
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,
CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂
Hydrochloric acid has a molecular weight of 36.45 g/mol compared to calcium carbonate's molecular weight of 100 g/mol. According to the equation above, 72.9 g of hydrochloric acid may dissolve 100 g of calcium carbonate.
x = (4.1 g HCl)(100 g CaCO3 / 72.9 HCl)
x = 5.62 g.
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Explanation
To find the mass from the given number of moles of the compound or molecule or atom.Use this formula
mass = moles x MM
where MM is the molar mass of the compound .To find the molar mass of CaCl2, consider the number of atoms of each element in the formula then multiply the number of elements with their atomic masses then finally add all the molecular weight.
CaCl2 has 1 Ca atom , 2 Cl atoms.
Ca = 1 x 40.07 = 40.07
Cl = 2 x 35.45 = 70.9
40.07 + 70.9 = 110.97 g / mol
mass = 0.89 x 110.97 = 98.76 g
Answer
98.76 g
Answer:
The answer is Light
Explanation:
In the electromagnetic spectrum there are many different types of waves with varying frequencies and wavelengths. They are all related by one important equation: Any electromagnetic wave's frequency multiplied by its wavelength equals the speed of light.
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Answer:
6626 g
Explanation:
Given that:
Density of water = 1.00 g/ml, volume of water = 42800 ml.
Since density = mass/ volume
mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g
Initial temperature of water = 22°C and final temperature of water = 45°C.
specific heat capacity for water = 4.184 J/g°C
ΔT water = 45 - 22 = 23°C
For iron:
mass = m,
specific heat capacity for iron = 0.444 J/g°C
Initial temperature of iron = 1445°C and final temperature of water = 45°C.
ΔT iron = 45 - 1445 = -1400°C
Quantity of heat (Q) to raised the temperature of a body is given as:
Q = mCΔT
The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.
Q water (gain) + Q iron (loss) = 0
Q water = - Q iron
42800 g × 4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C
m = 4118729.6/621.6
m = 6626 g
