Rutherford was the first person to make a model of an atom that was mostly accurate, the only thing is in his early model there were electrons and protons, at this time Rutherford did not know of a neutron and was not discovered until 1932.<span />
The weight force on an object in a gravitational field is given by

where

is the mass in kg and

is the acceleration<span> due to gravity at that place. Rearranging:
</span>

or

Explanation:
Venus is only slightly smaller than Earth, in both mass and radius, so this answer makes sense, when compared with the value of
<span>at Earth's surface.</span>
Answer:
See explanation
Explanation:
We convert the speed of the car to ms-1
90 × 1000/3600 = 25 ms-1
a) from;
F= ma
a= F/m
a= 8400/1050 = 8 ms-2
b) from
v= u - at
v= 0
u = 25 ms-1
a= 8 ms-2
t= ?
t = u/a = 25/8 = 3.1 s
From;
v^2 = u^2 - 2as
v= 0 ms-1
u^2 = 2as
s = u^2/2a
s= (25)^2/2 × 8
s= 625/16
s = 39 m
The simple pendulum concept and rotational kinematics relationships allow finding the result for the velocity relationship
- The shortest pendulum (w₁) has more speed than the longest pendulum (w₂)
w₁ =
w₂
The simple harmonic movement is a periodic movement where the restoring force is proportional to the elongation, in the case of the simple pendulum it is fulfilled for angles less than 10º. The expression for motion is
θ = θ₀ cos ωt
ω² = g / l
the angular velocity is defined by
w =
w = - θ₀ ω sin ωt
Where θ₀ is the initial angle or amplitude, w is the angular velocity, t the time, g the acceleration of gravity and l the length of the pendulum
Let's find the angular velocity for each pendulum
ω ₁ =
Indicate that the second pendulum length is
l₂ = 2 l₁
ω₂ =
the pendulum speed is maximum at the lowest point of the trajectory that occurs when the sine function has its maximum value
w = θ₀ω
Suppose that the two pendulums are released with the same initial angle
Pendulum 1
w₁ = θ₀
Pendulum 2
w₂ = θ₀
We look for the relationship between the two speeds
In conclusion, using the simple pendulum concept and the rotational kinematics relations we can find the result for the velocity relation
- The shortest pendulum (w₁) has more speed than the longest pendulum (w₂)
w₁ = √2 w₂
Learn more here: brainly.com/question/24159297
In the given four models of rockets, the rocket with the highest acceleration is rocket 2.
<h3>
Acceleration of the rockets</h3>
Acceleration is the rate of change of velocity with time. The acceleration of the rockets can also be determined from Newton's second law of motion with the applied force and mass of each rocket as shown below;
F = ma
where;
- F is the applied force
- m is the mass
- a is the acceleration
a = F/m
<h3>Rocket 1</h3>
a = 120/4.25
a = 28.24 m/s²
<h3>Rocket 2</h3>
a = 120/3.25
a = 36.92 m/s²
<h3>Rocket 3</h3>
a = 120/5.5
a = 21.82 m/s²
<h3>Rocket 4</h3>
a = 120/4.5
a = 26.7 m/s²
Thus, the rocket with the highest acceleration is rocket 2.
Learn more about acceleration here: brainly.com/question/14344386