I believe it is D.
hope it helps Yami ^-^
Answer:22.22m/s
Explanation:
Answer: 22.22 m/s
Explanation:
Using the law of conservation of momentum:
Initial momentum of the system = final momentum of the system.
mu+m'u' = mv+m'v'
where u and u' are the initial velocities.
v and v' are the final velocities.
mass of bullet, m = 0.04 kg
mass of the block of wood, m' = 0.5 kg
initial velocity of bullet, u = 300 m/s
initial velocity of block, u' = 0
after collision, block and bullet would move together with velocity v
⇒0.04 kg × 300 m/s + 0 = 0.54 kg × v
⇒ v = 22.22 m/s
Thus, the bullet and the wood block move together as one object with the speed 22.2 m/s.
Answer: 0.137 m/s
Explanation:
from the question we are given the following
mass of train A (Ma) = 150,000 kg
velocity of train A (Va) = 0.3 m/s
mass of train B (Mb) = 95,000 kg
velocity of train B (Vb) = -0.12 m/s
final velocity (V) = ?
mass of both trains = 245,000 kg
- to solve this question we apply the conservation of momentum
MaVa + MbVb = (Ma + Mb) x V
V = (MaVa + MbVb) / (Ma + Mb)
V = ((150,000 x 0.3) + (95,000 x (-0.12))) / (245,000)
V = -33600 / 245,000
V = 0.137 m/s
Answer:
20m
Explanation:
The two tens cancel each other out, as they are in opposite directions. Now we only care about the 20m, which if we have no 10's, will end up 20m away.
Answer:
The value is 
Explanation:
From the question we are told that
The angular speed is 
The distance between the minimum and maximum external position is 
Generally the amplitude of the crank shaft is mathematically represented as
=> 
=> 
Generally the maximum speed of the piston is mathematically represented as
=> 
=>
