Answer:
253.85 L
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O
From the balanced equation above, 4 moles of water vapor were produced.
Finally, we shall determine the volume of the water vapor produced as follow:
Mole water vapor (n) = 4 moles
Pressure (P) = 1 atm
Temperature (T) = 500 °C = 500 °C + 273 = 773 K
Gas constant (R) = 0.821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 4 ×0.0821 × 773
V = 253.85 L
Thus, the volume of water vapor obtained is 253.85 L
You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer
Answer:
ion X²- an element in group VI A.
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