The question is not complete. Proposed completed question is:
When aqueous solutions of sodium chloride and silver nitrate are mixed, a double-displacement reaction occurs. What is the balanced equation for the reaction?
A.
NaCl(aq) + AgNO3(aq) --------NaNO3(aq) + AgCl(aq)
B.
NaCl(aq) + AgNO3(aq) -------- NaNO3(aq) + 3AgCl(s)
C.
NaCl(aq) + AgNO3(aq) --------- NaNO3(aq) + AgCl(s)
D.
NaCl(aq) + AgNO3(aq) --------- Na(s) + AgNO3Cl(aq)
E.
NaCl(aq) + AgNO3(aq) --------- NaNO3(aq) + ClAg(s)
Answer is
A.
NaCl(aq) + AgNO3(aq) --------NaNO3(aq) + AgCl(aq)
Explanation:
Following the law of conservation of energy, the total number of atoms in the reactant side is equal to the total number of atoms in the product side.
The answer is; A
The force or weight and distance on both sides of the fulcrum is given by the following ratio;
MA = Fb/Fa = a/b (MA = Mechanical Advantage)
The greater the distance from the fulcrum on which force is applied to lift a load on the other side of the fulcrum, the less the effort required.
Ice floats because it is less dense than water. When water freezes, it creates a crystal lattice that occupies more volume than the water did. Because it is less dense, ice is displaced by water (and floats on top).
:)
Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g
