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Serggg [28]
3 years ago
14

1. Calculate the molar enthalpy of solidification (ΔHsolidification) when 10.00kJ of energy are lost as 30.00g of water are froz

en at 0ºC. Remember that this value will be negative, because energy is lost when water freezes. (Hint: start by finding out how many moles of water that are freezing)
Chemistry
1 answer:
kompoz [17]3 years ago
3 0

Answer:

The snow gains heat to melt (endothermic), then the water releases heat to freeze (exothermic). ... Beaker becomes hot because the reaction is pushing heat out from itself onto .... solidification (ΔHsolidification) when 10.00kJ of energy are lost as 30.00g of water.

Explanation:

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Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
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Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

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A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how ma
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Answer:

1.58\ \text{g}

Explanation:

10.11 g sample of NaBr contains 22.34% Na by mass

According to the law of constant composition the if one sample of NaBr has 22.34% of Na by mass then any other sample of NaBr will have the same percentage of the amount of Na.

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