(11 points) can y'all do science on this app just wondering?

Chemistry

2 answers:

agasfer [191]3 years ago

8 0

Yes you can!!!!!!!!!!!!

Shalnov [3]3 years ago

7 0

Of course, you can ask science questions under biology or another subject.

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Arsenate (AsO43-) is structurally and chemically similar to inorganic phosphate (PO43-), and many enzymes that act on phosphate

Lapatulllka [165]

Answer:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

Explanation:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

4 0

3 years ago

If a Ferrari with an initial velocity of 10m/s accelerates at a rate of 5m/s2 for 3 seconds. What will it’s final velocity be?

Reika [66]

Answer:

Explanation:

From first equation of motion, V = U + at

V = 10 + ( 5×3 )

V = 25 m/s

4 0

3 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li

meriva

Answer:

The standard enthalpy change for the reaction at $25^{0}\textrm{C}$ is -2043.999kJ

Explanation:

Standard enthalpy change ( $\Delta H_{rxn}^{0}$ ) for the given reaction is expressed as:

$\Delta H_{rxn}^{0}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]$