ANSWER IS A)
THE SPEED IS 25 M/S FOR BOTH PEOPLE
Answer:
The energy dissipated as the puck slides over the rough patch is 1.355 J
Explanation:
Given;
mass of the hockey puck, m = 0.159 kg
initial speed of the puck, u = 4.75 m/s
final speed of the puck, v = 2.35 m/s
The energy dissipated as the puck slides over the rough patch is given by;
ΔE = ¹/₂m(v² - u²)
ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)
ΔE = -1.355 J
the lost energy is 1.355 J
Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J
Through heat waves I'm pretty sure
Answer:
19320 K
Explanation:
The temperature of a star is related to its peak wavelength by Wien's displacement law:
where
T is the absolute temperature at the star's surface
is Wien's displacement constant
is the peak wavelength
Here we have
Substituting into the equation, we find
Answer:
R = 400 ohms.
Explanation: Voltage of the battery, V = 40 V. Current in the unknown resistor I = 100mA. Let R is the resistance of the resistor. It can be calculated using Ohm's law it gives the relationship between the voltage, resistance and current.. R = V/I. R = 40 V/10-¹A. R = 400 Ohm's. So, the value of the resistance of the resistor is 400 Ohm's
