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erica [24]
3 years ago
10

Standing waves on a 1.0m long string that is fixed at both ends are seen at successive frequencies of 24 hz and 36hz. what is th

e fundamental frequency and wave speed
Physics
1 answer:
kicyunya [14]3 years ago
3 0

The multiples of the fundamental frequency are the standing wave frequencies for a string.

Since 24 Hz and 36 Hz are consecutive frequencies, the fundamental frequency must be 36 −12 = 12 Hz. Meaning that the standing wave with frequency 36 Hz is the third harmonic (i.e., m = 3),

The wave speed fulfills the equation f1 = v / 2L where f1 is the fundamental frequency and L is the length of the string

So we can say that:

v = 2Lf1

= 2(1.0)(12)

= 24 m/s

 

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A golfer hits a golf ball with a club head velocity of 94 mph. Mass of golf club head (m): 190 g Mass of golf ball (ms): 46 g Co
MAXImum [283]

Answer:

Velocity of golf ball≅ 12.87mph    

Explanation:

Using the theory of conservative momentum to both the club head and the golf ball  we have;

Qi1 + Qi2= Qf1 + Qf2

Qi1: initial momentum for the club head

Qf1: final momentum for the club head

Qi2: initial momentum for the golf ball

Qf2: final momentum for the golf ball

momentum (Q) = Mass x velocity

which means the sum of the momentums of both club head and golf ball has to be the same before and after they have collided.

using the Coeficient of restitution e= 0.83 allows us to know what kind of collision we are dealing with, which is a partially elastic collision since

0> e=0.83 >1.

Qi1= 190 x 94= 17,860 mph.g

Qf1= 190 x Vf1

Qi2= 46 x 0= 0 mph.g

Qf2= 46x Vf2

Using the value of e to determine Vf2 as the final velocity of the golf ball:

e= \frac{Vf2- Vf1}{Vi1 - Vi2}

0.83= \frac{Vf2 - Vf1}{94 - 0}

Vf1= (0.83 x 94)+ Vf2

Vf1= 78.02 + Vf2

Qi1 + Qi2= Qf1 + Qf2

17,860 + 0 = 190xVf1 + 46xVf2    

17,860= 190x (78.02+Vf2) + 46xVf2

17,860= 14,823+ 190xVf2+46xVf2

Vf2≅ 12.87mph                

7 0
3 years ago
A circuit consists of a 9.0 v battery connected to three resistors (52 , 17 , and 140 ) in series. (a) find the current that flo
Fudgin [204]
A) TOTAL Resistance = 41+18+120 = 179 ohms 
<span>Current = V/R = 9 / 179 = 0.0503 A = 50.3 mA </span>

<span>B) V = I*R = .0503 * 41 = 2.06 V </span>

<span>C) V = I*R = .0503 * 18 = 0.91 V </span>

<span>D) V = I*R = .0503 * 120 = 6.03 V</span>
7 0
3 years ago
A stone is thrown from the top of a building with an initial velocity of 20 m/s downward. The top of the building is 60 m above
erastova [34]

Answer:

t = 2 s

Explanation:

In order to find the time taken by the stone to fall from the top of the building to the ground we can use 2nd equation of motion. 2nd equation of motion is as follows:

s = Vit + (0.5)gt²

where,

t = time = ?

Vi = Initial Velocity = 20 m/s

s = height of building = 60 m

g = 9.8 m/s²

Therefore,

60 m = (20 m/s)t + (0.5)(9.8 m/s²)t²

4.9t² + 20t - 60 = 0

solving this quadratic equation we get:

t = -6.1 s   (OR)   t = 2 s

Since, the time cannot be negative in magnitude.

Therefore,

<u>t = 2 s</u>

6 0
3 years ago
Please help ill give brainliest.
oee [108]
The answer is the last option "Respiration" 
3 0
3 years ago
Read 2 more answers
An arrow is shot upward from the roof of a building 75 m high with an initial speed of 40 m/s. If g = 10 m/s2 , what total dista
Elenna [48]

Answer:

60m

Explanation:

According to one of the equation of motions, v² = u²+2as where;

S is the distance

u is the initial velocity

v is the final velocity

a is the acceleration

Since the arrow is shot upwards, the body will experience a negative acceleration due to gravity i.e a = -g

Therefore our equation will become;

v² = u² - 2gS

Given u = 40m/s, g = 10m/s², S = 75m

Substituting to get the final velocity of the arrow we will have;

v² = 40²-2(10)(75)

v² = 1600 - 1500

v² = 100

v = √100

v = 10m/s

Total distance traveled is speed of the object × time taken

Total distance traveled = 10 × 6

= 60m

The arrow has therefore traveled 60m after 6seconds

3 0
3 years ago
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